Help please!!!<br> Can someone explain how to solve this please?

Can someone plz help me with this!

asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

$2x+y=10\\x-3y=-2$

To solve, start by isolating your first equation for y.

$2x+y=10\\y=-2x+10$

Now, plug this value of y into your second equation.

$x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4$

System #2: x=1

$x+2y=5\\2x+y=4$

Isolate your second equation for y.

$2x+y=4\\y=-2x+4$

Plug this value of y into your first equation.

$x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1$

System #3: x=6

$5x+y=33\\x=18-4y$

Isolate your first equation for y.

$5x+y=33\\y=-5x+33$

Plug this value of y into your second equation.

$x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6$

System #4: all real numbers (not included in your diagram)

$y=13-2x\\8x+4y=52$

Plug your value of y into your second equation.

$8x+4(13-2x)=52\\8x+52-8x=52\\0=0$

<em>all real numbers are solutions</em>

System #5: x=2

$x+3y=5\\6x-y=11$

Isolate your second equation for y.

$6x-y=11\\-y=-6x+11\\y=6x-11$

Plug in your value of y to your first equation.

$x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2$

System #6: no solution (not included in your diagram)

$2x+y=10\\-6x-3y=-2$

Isolate your first equation for y.

$2x+y=10\\y=-2x+10$

Plug your value of y into your second equation.

$-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2$

<em>no solution</em>

System #7: x=3

$y=10+x\\2x+3y=45$

Plug your value of y into your second equation.

$2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3$

3 0

3 years ago

this visual representation shows the sets of real numbers. classify the number −25. select all terms that are correct. natural w

vekshin1

-25 is an integer and a rational number.

<h3>What is number system?</h3>

A system of writing numbers is known as a number system.
It is the mathematical notation for consistently employing digits or other symbols to represent the numbers in a particular set.
It represents the arithmetic and algebraic structure of the numbers and gives each number a distinct representation.

Now,

Natural numbers are positive integers with a range of 1 to infinity; nevertheless, they do not include zero. -25 wouldn't be a natural number because it is a negative number.
A group of numbers known as a whole number consists of all positive integers and 0. This wouldn't be a whole number because -25 isn't a positive number.
Any real number that cannot be represented as the quotient of two integers is said to be irrational. Square roots of irrational numbers are also frequently seen. -25, however, is not a square root.
Any number that can be expressed as a ratio, or a fraction, of two integers, is referred to be a rational number. Fractions, decimals, negative decimals, and other rational numbers are very prevalent. Since -25 can be represented as a ratio of two numbers. it is a rational number.
A whole number that can be either positive, negative, or zero is known as an integer. As -25 is negative and a whole number( when positive), it is an integer.

Hence, -25 is an integer and a rational number.

To learn more about number system, refer to the link: brainly.com/question/13162939

#SPJ4

6 0

1 year ago

Solve each equation check your solution<br> 49=-7(t+1)

enyata [817]

49 = -7 (t + 1)
49 = -7t + 7
-7 -7
42 = -7t
÷ -7 ÷ -7
-6 = t

t = -7

5 0

3 years ago

Read 2 more answers

HELP ME ASAP........

butalik [34]

The sample at option B, {0, 2} is not a part of the sample space of a spinner when spun two times.

<h3>What is a sample space?</h3>

The set consists of all the possible outcomes of an event called sample points, which is said to be a sample space.

<h3>Calculation:</h3>

It is given that,

a spinner has 5 sections of equal area and each section is numbered from 1 to 5.

If the spinner is spun two times, then the possible outcomes are 25. They are:

{(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5)}

So, from the given options, the sample {0, 2} is not possible since there is no such a section on the spinner named 0.

Learn more about sample space here:

brainly.com/question/9773761

#SPJ1

8 0

1 year ago

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B833%7D%20" id="TexFormula1" title=" \sqrt[5]{833} " alt=" \sqrt[5]{833} "

zepelin [54]

Here is the simplified answer to this equation: 5 goes into 8 once, so you would bring the 5 on top and subtract 8, the first number, by 5. The answer is three. Bring down the 3 next to the 8. You now have 33. 5 goes into 33 6 times, which equals 30. Write 30 underneath 33 and bring the 6 to the top next to the 1. Bring down the 3 next to the last 3. You now have 33. 5 goes into 33 (once again) 6 times. Write 6 on top next to the last 6. 33 - 30 = 3. 5 cannot go into 3 since it is larger, so 3/5 you write 3/5 as a decimal next to 166 at the top (3 at the bottom and 5 is the larger number at the divisor spot). The decimal is 0.6. Therefore, your answer should be 166.6. To make sure, multiply 166.6 x 5. Hopefully, you get 833.

Hope I helped!

4 0

3 years ago

Help please!!! Can someone explain how to solve this please?