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Iteru [2.4K]
3 years ago
15

Help me please boyos

Mathematics
2 answers:
luda_lava [24]3 years ago
3 0

Answer:

para wala nang makasagot

Bas_tet [7]3 years ago
3 0

Answers:

Expression 1 - Option 1

Expression 2 - Option 2

Expression 3 - Option 3

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What are the solutions of x2 = 8 - 5x?
jonny [76]

Answer:

That can be re-written:

x^2 + 5x -8 = 0

We use the Quadratic Formula

a=1

b = 5

c = -8

x = [-b +- sq root (b^2 - 4ac) ] / 2a

x = [-5 +- sq root (25 - - 32)] / 2

x1 = [-5 + sq root (57)] / 2

x1 = 1.27491722

x2 = [-5 - sq root (57)] / 2

x2 = -6.2749172176

Step-by-step explanation:

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<u><em>Rotation and Revolution are two motions of the earth.</em></u>

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Solve the following quadratic inequality 2x^2+3x-5&gt;0
madreJ [45]

Answer:

x < -2.5 and x > 1

Step-by-step explanation:

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3 years ago
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The answer to this question is:

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Does the point (-4, 2) lie inside or outside or on the circle x^2 + y^2 = 25?​
stiv31 [10]

Given equation of the Circle is ,

\sf\implies x^2 + y^2 = 25

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2

Here we can say that ,

• <u>Radius</u> = 5 units

• <u>Centre </u> = (0,0)

<u>Finding</u><u> </u><u>distance</u><u> between</u><u> </u><u>the </u><u>two </u><u>points</u><u> </u><u>:</u><u>-</u><u> </u>

\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }

  • Here we can see that the distance of point from centre is less than the radius.

<u>Hence </u><u>the</u><u> </u><u>point</u><u> </u><u>lies </u><u>within</u><u> </u><u>the </u><u>circle</u><u> </u><u>.</u>

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3 years ago
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