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White raven [17]
3 years ago
6

48

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
4 0
2.20 kg + 1.90 kg

*1*
2.20
+1.90
4.10

Ans=4.10 kg
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<img src="https://tex.z-dn.net/?f=3%286%20%2B%207%29%20%20" id="TexFormula1" title="3(6 + 7) " alt="3(6 + 7) " align="absmiddl
scoray [572]

Answer:

39

Step-by-step explanation:

3(6+7)

=18+21

=39

or

3(6+7)

=3(13)

=39

8 0
3 years ago
Working alone, Darryl can mop a warehouse in 11 hours. Elisa can mop the same warehouse in 9
Harrizon [31]

Answer:

  • ≈ 5 hours

Step-by-step explanation:

<u>Time needed if they work together:</u>

  • 1 / (1/11 + 1/9) =
  • 1/ (20 / 99) =
  • 99/20 ≈ 5 hours
3 0
3 years ago
A glacier advances toward the sea 0.004 mile anually. In 2010 the front of the glacier is 6.9 miles from the mouth of the sea. H
olchik [2.2K]

You know where the glacier is now, and how far it moves in
one year.  The question is asking how close to the sea it will be
after many years.

Step-1 ... you have to find out how many years

Step-2 ... you have to figure out how far it moves in that many years

Step-3 ... you have to figure out where it is after it moves that far

The first time I worked this problem, I left out  the most important
step ... READ the problem carefully and make SURE you know
the real question.  The first time I worked the problem, I thought
I was done after Step-2. 

============================

Step-1:  How many years is it from 2010 to 2030 ?

               (2030  -  2010)  =  20 years .


Step-2:  How far will the glacier move in 20 years ? 

               It moves 0.004 mile in 1 year.

              In 20 years, it moves 0.004 mile 20 times

              0.004 x 20  =  0.08 mile


Step-3: How far will it be from the sea after all those years ?

              In 2010, when we started watching it, it was 6.9 miles
              from the sea.

              The glacier moves toward the sea.
               In 20 years, it will be  0.08 mile closer to the sea.
               How close will it be ?

               6.9 miles  -  0.08 mile  =  6.82 miles  (if it doesn't melt)

7 0
3 years ago
Please Help! Show all the steps!
likoan [24]

You can start by subtracting different equations from each other.

3x + 2y + 3z = 1

subtract

3x + 2y + z = 7

2z = -6

divide by 2

z = -3

add the following two expressions together:

3x + 2y + z = 7

3x + 2y + 3z =1

6x + 4y + 4z = 8

subtract the following two expressions:

6x + 4y + 4z = 8

5x + 5y + 4z = 3

x - y = 5

^multiply the whole equation above by 3

3x - 3y = 15

subtract the following two expressions:

3x - 3y = 15

3x + 2y = 10

-5y = 5

divide each side by -5

y=-1

take the following expression from earlier:

x - y = 5

substitute y value into above equation

x - - 1 = 5

2 negatives make a positive

x + 1 = 5

subtract 1 from each side

x = 4

Therefore x = 4, y = -1, z = -3

I checked these with all 3 equations and they worked :)

(it's quite complicated, comment if you don't understand anything) :)

7 0
3 years ago
What are the roots of the equation 4x2 = 36x – 87 in simplest a + bi form?
sammy [17]

Answer:

x = 87/28

Step-by-step explanation:

6 0
3 years ago
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