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3 years ago

A triangle has one angle that measures 26 degrees, one angle that measures 116 degrees, and one angle that measures 38 degrees.

Mathematics

2 answers:

Vadim26 [7]3 years ago

4 0

B is. Answer and it is Obtuse Triangle

Alika [10]3 years ago

3 0

Answer:

é çretac )pizaão , e q mal muaito nesab a

Step-by-step explanation:

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You have exactly $120 to spend on a new outfit. If your state has 8% sales tax, what is the highest pre-price tax you can pay wi

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You have exactly $120 to spend on a new outfit. If your state has 8% sales tax, what is the highest pre-tax price you can pay without going over budget?8% of 120 is 110.4

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3 years ago

18. What's 7?8 as a decimal? A. .78 B. 8.7 C. .875 D. 7.8

kenny6666 [7]

Each 1/8 is 0.125, so 7*0.125 in relation to 7/8 as a decimal is 0.875. Answer C.

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3 years ago

use the elimination method to solve the system of equations. choose the correct ordered pair. 3x + 6y = 36 and 3x - 6y = 0

VladimirAG [237]

3x + 6y = 36

+ 3x - 6y =0

------------------------

6x = 36

x = 36/6

x = 6

3(6) - 6y = 0

18 - 6y = 0

-6y = -18

y = 3

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3 years ago

Read 2 more answers

D/d{cosec^-1(1+x²/2x)} is equal to

SIZIF [17.4K]

Step-by-step explanation:

$\large\underline{\sf{Solution-}}$

$\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

Let assume that

$\rm :\longmapsto\:y = {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

We know,

$\boxed{\tt{ {cosec}^{ - 1}x = {sin}^{ - 1}\bigg( \dfrac{1}{x} \bigg)}}$

So, using this, we get

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2x}{1 + {x}^{2} } \bigg)$

Now, we use Method of Substitution, So we substitute

$\red{\rm :\longmapsto\:x = tanz \: \rm\implies \:z = {tan}^{ - 1}x}$

So, above expression can be rewritten as

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2tanz}{1 + {tan}^{2} z} \bigg)$

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( sin2z \bigg)$

$\rm\implies \:y = 2z$

$\bf\implies \:y = 2 {tan}^{ - 1}x$

So,

$\bf\implies \: {cosec}^{ - 1}\bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = 2 {tan}^{ - 1}x$

Thus,

$\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

$\rm \: = \: \dfrac{d}{dx}(2 {tan}^{ - 1}x)$

$\rm \: = \: 2 \: \dfrac{d}{dx}( {tan}^{ - 1}x)$

$\rm \: = \: 2 \times \dfrac{1}{1 + {x}^{2} }$

$\rm \: = \: \dfrac{2}{1 + {x}^{2} }$

Hence, 

$\purple{\rm :\longmapsto\:\boxed{\tt{ \dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = \frac{2}{1 + {x}^{2} }}}}$

Hence, Option (d) is correct.

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2 years ago

200 students in a class took an examination in French and English. 180 of them passed in English and 80 passed in both French an

MakcuM [25]

Answer:

500

Step-by-step explanation:

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3 years ago