I took five years before and it was hard for me to remember the postualates. I found it helpful to practice proving problems that involved the postualate. Some postualates like SAS are just abbreviations. SAS- Side-Angle-Side
Answer:
X=7 and y=6
Step-by-step explanation:
Y=-2x + 20.......eq(i)
6x-5y=12.....eq(ii)
Now, putting y= - 2x +20 in eq (ii)
6x - 5(-2x + 20)=12
6x + 10x - 100 = 12
16x=12+100
X=112 /16
X=7
Then, putting x=7 in eq (i)
Y=-2*7 +20
=-14 +20
=6
<span>y= 2x ^2 - 8x +9
</span>y = a(x - h)2 + k, where (h, k) is the vertex<span> of the parabola
</span>so
y= 2x ^2 - 8x + 9
y= 2x ^2 - 8x + 8 + 1
y = 2(x^2 - 4x - 4) + 1
y = 2(x - 2)^2 + 1 ....<---------<span>vertex form</span>
A rhombus has four equal sides. If the perimeter of this rhombus is 164, then the length of one side is 164/4, or 41.
Draw this rhombus. Label all four sides with "41." Label the longer diagonal 80 and the half length of that diagonal 40. You will see inside the rhombus four congruent triangles with hypotenuse 41, leg 10 and unknown height. Thus, this unknown height is found by solving x^2 + 40^2 = 41^2, and x^2=9, so that the length of the shorter diagonal is 2(2) = 18 (answer).
