you cant really predict how many bagels will be sold the next morning because of different scenarios but mathematically speaking if you compare plain bagels to total bagels you get 3/15 so if you multiply the denominator by 1 1/4 to get twenty as the denominator then you have to do the same to the numerator to get a fraction of 3.75/20 or roughly 3-4 plain bagels sold
Answer:
x=4 :y=-8
Just ut Equation in Scientific Calculator or Symbolab App or WEb search Equation solver
.725 multiplied by 4500=362.5
750+3262.5=4012.5
Answer:
0.5981 = 59.81% probability that three or less of the selected adults have saved nothing for retirement
Step-by-step explanation:
For each adult, there are only two possible outcomes. Either they save nothing for retirement, or they save something. The probability of an adult saving nothing for retirement is independent of any other adult. This means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
20% of adults in the United States save nothing for retirement (CNBC website).
This means that 
Suppose that sixteen adults in the United States are selected randomly.
This means that 
What is the probability that three or less of the selected adults have saved nothing for retirement?
This is:

In which






0.5981 = 59.81% probability that three or less of the selected adults have saved nothing for retirement