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Ber [7]
4 years ago
14

Jules kicks a soccer ball off the ground and into the air with an initial velocity of 25 feet per second. Assume the starting he

ight of the ball is 0 feet. Approximateley what maximum height does the soccer ball reach.
Mathematics
1 answer:
kondor19780726 [428]4 years ago
6 0

Use the formula h(t) = -16t^2 + vt + s,

where t = time in air,

v = starting upward velocity,

s = the objects starting height.

from ground (s), the starting height is 0,

the ball's initial velocity (v) 25 feet per second

Solve:

v - 16t^2 + (25)t + 0

= -16t^2 + 25t. 0

Factor:

= -16t^2 + 25t

Find GCF:

0 = -16t^2 + 25t

Divide both sides by (t)

t(-16 + 25) = 0

t = 0; -16 + 25 = 0

Now Subtract 25 from both sides of equation:

-16 = -25

divide both sides by -16 to get -25/-16

= 1.56

Rounds to 1.60, or 1.6

Answer: 1.6 Seconds it will take for soccer ball to hit the ground again.

First part of the Equation: Answer: 9.8Ft. Soccer ball will reach at maximum height.

Hope that helps!!!! : )

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lana66690 [7]
2 pounds.

60(20) = 1200 = area
If 300 square feet requires 1/2 pound, you can divide 1200 square feet by 300 square feet.

1200/300=4
4 times 1/2
4(1/2)=2

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3 years ago
The IQ test is designed such that the scores on it are normally distributed with a mean of 100 and a standard deviation of 15. I
kozerog [31]

Answer:

130

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5 0
3 years ago
Please help I am on number 1 please explain
jeka57 [31]
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5 0
3 years ago
This seems easy but i’m not sure how to do it, anyone know the answer
Pie
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Hope this helps!
4 0
3 years ago
Value of P: 3/15(p+10)=-15
ArbitrLikvidat [17]
<span>Step  1  :</span> 1 Simplify — 5 <span>Equation at the end of step  1  :</span> 1 (— • (p + 10)) - -15 = 0 5 <span>Step  2  :</span><span>Equation at the end of step  2  :</span> (p + 10) ———————— - -15 = 0 5 <span>Step  3  :</span>Rewriting the whole as an Equivalent Fraction :

<span> 3.1 </span>  Subtracting a whole from a fraction 

Rewrite the whole as a fraction using <span> 5 </span> as the denominator :

-15 -15 • 5 -15 = ——— = ——————— 1 5

<span>Equivalent fraction : </span>The fraction thus generated looks different but has the same value as the whole 

<span>Common denominator : </span>The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

<span> 3.2 </span>      Adding up the two equivalent fractions 
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

(p+10) - (-15 • 5) p + 85 —————————————————— = —————— 5 5 <span>Equation at the end of step  3  :</span> p + 85 —————— = 0 5 <span>Step  4  :</span>When a fraction equals zero :<span><span> 4.1 </span>   When a fraction equals zero ...</span>

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the <span>denominator, </span>Tiger multiplys both sides of the equation by the denominator.

Here's how:

p+85 ———— • 5 = 0 • 5 5

Now, on the left hand side, the <span> 5 </span> cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :
   p+85  = 0

Solving a Single Variable Equation :

<span> 4.2 </span>     Solve  :    p+85 = 0<span> 

 </span>Subtract  85  from both sides of the equation :<span> 
 </span>                     p = -85 

One solution was found :                  <span> p = -85</span>
7 0
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