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Gre4nikov [31]
2 years ago
14

3√6×2√3=...5√12+3√3=...​

Mathematics
1 answer:
ikadub [295]2 years ago
6 0

Answer:

  • 3\sqrt{6}\times \:2\sqrt{3}=18\sqrt{2}
  • 5\sqrt{12}+3\sqrt{3}=13\sqrt{3}

Step-by-step explanation:

                                                        1)

Given the expression

3\sqrt{6}\:\times \:2\sqrt{3}

\mathrm{Factor\:integer\:}6=3\times \:2

=3\sqrt{3\times \:2}\times \:2\sqrt{3}

\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}

=3\sqrt{3}\sqrt{2}\times \:2\sqrt{3}

\mathrm{Apply\:radical\:rule}:\quad \sqrt{a}\sqrt{a}=a

=3\times \:2\times \:3\sqrt{2}

=18\sqrt{2}

Thus,

3\sqrt{6}\times \:2\sqrt{3}=18\sqrt{2}

                                                        2)

Given the expression

5\sqrt{12}+3\sqrt{3}

\:=\:5\sqrt{\left(4\right)\left(3\right)}+3\sqrt{3}

=\:5\times 2\sqrt{\left(3\right)}+3\sqrt{3}

=10\sqrt{3}+3\sqrt{3}

\mathrm{Add\:similar\:elements:}\:10\sqrt{3}+3\sqrt{3}=13\sqrt{3}

=13\sqrt{3}

Thus,

5\sqrt{12}+3\sqrt{3}=13\sqrt{3}

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dmitriy555 [2]

see the attached figure to better understand the problem

we have that

cos(A)=\frac{1}{5} \\ AB=12\ units\\ CD=2\ units

Step 1

<u>Find the value of AC</u>

we know that

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cos (A)=(AC/AB)\\AC=AB*cos(A)

substitute the values in the formula

AC=12*(1/5)\\ AC=2.4\ units

Step 2

<u>Find the value of BC</u>

we know that

in the right triangle ABC

Applying the Pythagorean Theorem

AB^{2} =AC^{2}+BC^{2}\\ BC^{2}=AB^{2} -AC^{2}

substitute the values

BC^{2}=12^{2} -2.4^{2}\\BC^{2}= 138.24\\ BC=11.76\ units

Step 3  

<u>Find the value of BD</u>

we know that

in the right triangle BCD

Applying the Pythagorean Theorem

BD^{2} =DC^{2}+BC^{2}

substitute the values  

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belka [17]
<h2>Hello!</h2>

The answer is:

The correct option is the option D

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<h2>Why?</h2>

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We need to use the following free fall equation:

V_{f}=V_{o}-g*t

Where:

V_{f} is the final speed.

V_{o} is the initial speed.

g is the acceleration due to gravity.

t is the time.

We are given the following information:

V_{f}=8.15\frac{m}{s}

V_{o}=0\frac{m}{s}

t=5seconds

Then, using the formula to isolate the acceleration, we have:

V_{f}=V_{o}-g*t

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Now, substituting we have:

g=\frac{V_{o}-V_{f}}{t}

g=\frac{0-8.15\frac{m}{s}}{5seconds}=-1.63\frac{m}{s^{2}}

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g=1.63\frac{m}{s^{2}}

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Have a nice day!

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3 years ago
Please help it due in a lil bit <br><br><br> please and thank u
vladimir2022 [97]

Answer:

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sin(60)= \frac{x}{16}

x = 16 × sin(60)

x = 13.9

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8 0
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