Answer:
y=a(x-p)(x-q)
y=a(x+2+√2)(x+2-√2)
passing through point (-1,1)
substitute
1=a(-1+2+√2)(-1+2-√2)
1=a(1+√2)(1-√2)
1=a(1-2)
1=a(-1)
a=1/(-1)
a=-1
y=-(x+[2+√2])(x+[2-√2])
y=-(x2+4x+2)
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Answer:
Step-by-step explanation:
As you can observe in the image attached, the line that best fits passes through point B and C. That means we can use those point to find the slope of such line.
Where 
and 
So, the slope of the line that best fits is -11, approximately.
Now, we use the point-slope formula to find the equation.
Therefore, the line that best fits is approximately.
Remember, when we estimate a line for some data on a scatterplot, we are calculating an approximation, that's why we also said "approximately", because the line is an approximation where the majority of point meet.
Answer:
f(g(-4)) = 13.
g(f(-4)) = -3.
Step-by-step explanation:
g(-4) = (-4)^2 + 3(-4) - 1
= 3.
so f(g(-4))
= f(3)
= 2(3) + 7
= 13.
f(-4) = 2(-4) + 7
= -1.
so g (f(-4))
= g(-1)
= (-1)^2 - 3 - 1
= -3.
Answer:
The true true level of significance of this test is more than 0.01.
Step-by-step explanation:
No standard deviation and we are told that the investigator still used z rather than the more appropriate t - distribution.
This method of using the z-distribution when standard deviation is unknown will definitely result in a smaller critical value and this in turn simply means that the p-value will be smaller than what it should really be.
Thus, it means the critical value is getting closer to the mean value than the way it should be.
Therefore, means that for a given significance of 0.01 and using the z-distribution under this no standard deviation situation, the true true level of significance of this test is more than 0.01.
Answer:
14
Step-by-step explanation:
we can use sin(30⁰) to solve this and the units will be 14
