Answer:
Probability of missing two passes in a row is 0.08.
Step-by-step explanation:
Event E = A football player misses twice in a row.
P(E) = ?
Event X = Football player misses the first pass
P(X) = 0.4
Event Y = Football player misses just after he first miss
P(Y) = 0.2
Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:
P(E) = P(X).P(Y)
P(E) = 0.4*0.2
P(E) = 0.08
X^1/2 - x
-2x^3 - x^1/2 - x
-2x^3 - 2x
i think this is it
Answer:
SA = 3.04m²
Step-by-step explanation:
SA = 2 x ( Length x Width + Width x Height + Length x Height )
SA = 2 x ( 0.4 x 1 + 0.4 x 0.8 + 1 x 0.8 )
SA = 2 x ( 0.4 + 0.32 +0.8)
SA = 2 x 1.52
SA = 3.04 m²
I wish this could help you !
Two right angles? that's what I would think
