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3 years ago

Consider the procedure used below to solve the given equation.

Mathematics

1 answer:

muminat3 years ago

5 0

The first mistake was made in step 1 because they took out the x’s it should be 10x-25+2x+8=43

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Jonah earned $5 more than half of Karen's salary, k. Which of the following expressions represents Jonah's earnings?

Mashutka [201]

Answer:

one half×k + 5 is the correct expression that represents Jonah's salary

4 0

3 years ago

Read 2 more answers

(4y − 3)(2y2 + 3y − 5)

IRINA_888 [86]

Answer:

$8y^3 + 6y^2- 29y + 15$

Step-by-step explanation:

$(4y-3)(2y^2+3y-5)\\4y(2y^2 + 3y - 5) - 3(2y^2+3y-5)\\8y^3+12y^2-20y-3(2y^2+3y-5)\\8y^3+12y^2-20y-6y^2-9y+15\\8y^3+6y^2-29y-9y+15\\= 8y^3+6y^2-29y+15$

6 0

3 years ago

The probability of event ???? is P(????)=0.5 , and the probability of event ???? is P(????)=0.7 . Are ???? and ???? disjoint? no

ki77a [65]

Answer:

A and B are not disjoint.

Step-by-step explanation:

Given that there are two events A and B with prob

P(A)=0.5,

P(B)=0.7

If A and B are disjoint, there should not be any common element between A and B

P(AB) should be 0

But here we find P(A) + P(B) = 1.2>1

Since total probability is 1, there must be 0.2 atleast in P(AB)

which implies A and B cannot be disjoint.

A and B are not disjoint.

3 0

3 years ago

The volume, V, of the right circular cone with radius r.

Paha777 [63]

Answer:

radius^2 = 3 * Volume / (PI * height)

radius^2 = 3 * (142 cc / 3.14159265 * 8.5)

radius^2 = 3 * (142 cc / 26.703537525 )

radius^2 = 15.9529425493

radius = 4.0 cm

Step-by-step explanation:

3 0

3 years ago

Solve and graph the compound inequalities. (You don’t need to graph it on a line plot but if you could that would be great!)

lidiya [134]

Part A

$-12 < 5x - 2 < 13\\\\-12+2 < 5x - 2+2 < 13+2 \ \text{ ... add 2 to all sides}\\\\-10 < 5x < 15\\\\-10/5 < 5x/5 < 15/5 \ \text{ ... divide all sides by 5 to isolate x}\\\\-2 < x < 3\\\\$

To graph this, we plot open holes at -2 and 3 on the number line. Shade between these open holes to represent values between -2 and 3, but we don't include the endpoints.

See figure 1 below.

===============================================

Part B

Solve the first inequality to get

$3x < -9\\\\3x/3 < -9/3\\\\x < -3\\\\$

Now solve the second inequality

$2x \ge x+1\\\\2x-x \ge x+1-x\\\\x \ge 1\\\\$

We have $x < -3 \ \text{ or } \ x \ge 1$

The graph will have an open hole at -3 and a closed/filled in circle at 1. We shade everywhere but the region between these marked values. The left portion in blue represents stuff smaller than -3; the right portion in red represents values equal to 1 or larger.

See figure 2 below.

4 0

2 years ago