Consider the procedure used below to solve the given equation.
1 answer:
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To find the zeros of this function, we must first set the entire function equal to 0
f(x) = x² - 2x - 15 = 0
Since this is a quadratic function, we must use the quadratic formula, which is:
Let's assign a, b, and c using our first function
x² means a = 1 (because it could be written as 1x²)
-2x means b = -2
-15 means c = -15
Now let's plug those in:
which simplifies to:
Simplified further:
And divide it by the 2 on the bottom gives us:
2+4 = 6
2-4 = -2
So the zeros of this function are -2 and 6
f(x) = x² - 2x - 15 = 0
Since this is a quadratic function, we must use the quadratic formula, which is:
Let's assign a, b, and c using our first function
x² means a = 1 (because it could be written as 1x²)
-2x means b = -2
-15 means c = -15
Now let's plug those in:
which simplifies to:
Simplified further:
And divide it by the 2 on the bottom gives us:
2+4 = 6
2-4 = -2
So the zeros of this function are -2 and 6
TeX rendering has been iffy at best on this site for the past few days, at least in my experience. I've attached a solution below.
