The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using

Substitute the known values in the above equation

Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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Let n be the 40%, and 100-n be the 10%. Then:
.4n+.1(100-n)=.22(100)
.3n+10=22
.3n=12
n=40
The candy distributor needs 40kg of 40%, and 60kg of 10%
☺☺☺☺
The answer is 8 3/4. Hope this helps
Answer:
The answer is B
Step-by-step explanation:
This is because they subtract the cost of ingredients from the sum they earned to calculate the profit :)