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UNO [17]
3 years ago
7

Find the area and perimeter of the regular polygon

Mathematics
1 answer:
fgiga [73]3 years ago
5 0
Answer: area= 130.88 m^2
perimeter= 42.08 m

I hope that helps, and I apologize in advance if it’s not right.
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I need help can you guys help me out thank you!! p.s. the word is meaters
Gala2k [10]
It’s 76 meters hoped it helped!
6 0
3 years ago
Hi pls help! ill mark u brainliest
mina [271]

Answer:

450+70x

Step-by-step explanation:

x is the number of months and 450 is the actual amount of money in his bank account

8 0
3 years ago
Which of the following random variables should be considered continuous? Select one: a. The number of cars owned by a randomly c
kolbaska11 [484]

The Random Variable that should be considered continuous is "The time it takes for a randomly chosen athlete to run 200 meters" , the correct option is (c) .

In the question ,

four random variables are given , we have to select the random variable that is continuous .

A Continuous Random Variable is a random variable X , which can take any value in its domain or in an interval or the union of intervals on the real line is called Continuous random variable .

For Example : weight of middle aged people lying between 40 Kg and 150 Kg .

From the given options ,

the option (c) , the time taken for a randomly chosen athlete to run 200 meters is a interval of time ,

So ,it is can be called as Continuous Random Variable .

Therefore , the option that represents Continuous Random Variable is option(c) .

The given question is incomplete , the complete question is

Which of the following random variables should be considered continuous ? Select one:

(a) The number of cars owned by a randomly chosen adult male

(b) The number of orders received by a mail-order company in a randomly chosen week

(c) The time it takes for a randomly chosen athlete to run 200 meters  

(d) The numbers of brothers a randomly chosen person has .

Learn more about Continuous Random Variable here

brainly.com/question/17238189

#SPJ4

3 0
1 year ago
Which expression is equivalent to sec^2x − 1? a. cot2x b. tan2x c. csc2x d. cos2x
Nesterboy [21]
Sec^2 x - 1 = tan^2x

Proof:
Sec^2x = 1+ tan^2x

1/cos^2x = 1 + sin^2x/cos^2x

<span>1/cos^2x - sin^2x/cos^2x = 1
</span>Using common denominator:
(1-sin^2x)/cos^2x = 1
sin^2x + cos^2 x = 1
cos^2 x = 1 - sin^2x
Substituting : 
cos^2x/<span>cos^2x = 1
</span>1 = 1
Left hand side = right hand side 
4 0
3 years ago
Read 2 more answers
PLEASE HELP!! 25 POINTS !!! Graphing
Sunny_sXe [5.5K]
A = 6, 2
B = 3, 4
C = -10, 3
D = -4, 5
E = -5, -3
F = -4, -2
G = 3, -8
4 0
3 years ago
Read 2 more answers
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