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oee [108]
4 years ago
12

Find the range for the function: y=x-7 {-3,0,2,5}

Mathematics
1 answer:
trasher [3.6K]4 years ago
8 0

Answer:

Range is : { -10, -7, -5, -2 }

Step-by-step explanation:

Given:

The function is given as:

y=x-7

The domain of the function = { -3, 0, 2, 5 }

A function's input is called its domain and a function's output is called its range.

The range depends on the domain values. So, the values of 'y' are the values of range and the values of 'x' are the values of domain.

Here, the domain is given as:

Domain = { -3, 0, 2, 5 }

We need to find the values of 'y' for each value of 'x' taken from the domain set.

Plug in x=-3. This gives,

y=-3-7=-10

Plug in x=0. This gives,

y=0-7=-7

Plug in x=2. This gives,

y=2-7=-5

Plug in x=-5. This gives,

y=5-7=-2

Therefore, the set of all values of 'y' is the range.

Range is equal to { -10, -7, -5, -2 }.

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PLEASE HELP ASAP!!!!!!!!
steposvetlana [31]

Answer:

4.6.

Step-by-step explanation:

The rocket hits the ground when h(t) = 0. So

-16t^{2} + 72t + 7 = 0

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

-16t^{2} + 72t + 7 = 0

So

a = -16, b = 72, c = 7

Then

\bigtriangleup = 72^{2} - 4*(-16)*7 = 5632

t_{1} = \frac{-72 + \sqrt{5632}}{2*(-16)} = -0.1

t_{2} = \frac{-72 - \sqrt{5632}}{2*(-16)} = 4.6

Time is a positive measure, so the answer is 4.6.

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3 years ago
How do you write explanation form for 9×9×9×9​
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Step-by-step explanation:

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If m∠4 = 100°, what is m∠5?
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