Question: What is the area of the real object that the scale drawing models?

Kobotan [32]

<h3>Answer: </h3><h3>See the attached image below for the table</h3>

In column 1 we have the x values 0, 4, 8, 12

In column 2, we have the y values 1, 2, 3, 4

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Explanation:

We can start with any x value we want. I find that 0 is easiest to work with, so why not start at x = 0. For the sake of not repeating, I'll use y = 1 as the start value for y.

The first row of the table is x = 0 and y = 1.

A slope of 1/4 means rise/run = 1/4. So rise = 1 and run = 4.

A rise of 1 indicates y goes up by 1. A run of 4 means x increases by 4.

So put together, slope = 1/4 means each time x goes up by 4, y goes up by 1.

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If we started at x = 0, then going up by 4 leads to x = 4. If y starts at y = 1, then going up by 1 leads to y = 2.

The second row of the table is x = 4 and y = 2

We'll repeat the pattern of "add 4 to x, add 1 to y" getting the third row having x = 8 and y = 3

We can repeat as many times as we want. Doing another "up 1, over to the right 4" movement lands us on (x,y) = (12, 4)

The completed table is shown below in the attached image.

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If you were to use the slope formula with any two rows of the table, then you should get m = 1/4

Let's do the first two rows

m = (y2-y1)/(x2-x1)

m = (2-1)/(4-0)

m = 1/4

I'll let you check the other pairs of rows.

3 0

3 years ago

Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)

Leni [432]

Alrighty

remember some rules
$(ab)^c=(a^c)(b^c)$
and
$x^{-m}=\frac{1}{x^m}$
and
$x^0=1$ for all real values of x
and
$(a^b)^c=a^{bc}$
and
$(\frac{a}{b})^c=\frac{a^c}{b^c}$
and
(a/b)/(c/d)=(ad)/(bc)
and
$(a^b)(a^c)=a^{b+c}$
and
$\frac{a^m}{a^n}=a^{m-n}$
and don't forget pemdas
example: $-x^m=-1(x^m)$ but $(-x)^m=(-1)^m(x^m)$

so

4.
$(\frac{c^{-2}}{2})^{-2}=$

$\frac{(c^{-2})^{-2}}{2^{-2}}=$

$\frac{c^4}{\frac{1}{2^2}}=$

$\frac{c^4}{\frac{1}{4}}=$

$4c^4$

5.

$\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=$

$\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=$

$\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=$

$\frac{(a^4bc^5)b^3}{(-1)(a^2)}=$

$\frac{-a^4b^4c^5}{a^2}=$

$-a^2b^4c^5$

3 0

3 years ago

What is the unit rate $1.29 for 15oz to nearest tenth

Nina [5.8K]

Answer:

The unit price of an item is the cost for each unit.

The unit price may be calculated for several reasons.

It will allow an easy comparison of the cost of the same quantity of items that come in different sizes.

For example, Company A sells peaches in a can. Their can holds 16 oz of peaches at a price of $1.60. Company B also sells peaches in a can, but their can holds 10 oz of peaches at a price of $1.10. At first glance, Company B looks like they might have cheaper peaches because of the lower overall price, but when you calculate the unit price, you get a more accurate way to compare.

For Company A, $1.60 ÷ 16oz = $0.10 per ounce.

For Company B, $1.10 ÷ 10oz = $0.11 per ounce.

The peaches are measured with ounces as the unit, so now that we have unit prices, we can definitely tell that Company A is the better deal, if you like peaches!

Unit price can also be helpful to find the cost of a single item when many items are purchased together. This may be required if the items are going to be divided up and resold. It could also be useful if several people will pay together with each person paying their fair share of the cost based on how many items they receive.

Step-by-step explanation:

5 0

3 years ago

Relationship B has a lesser rate than Relationship A. This graph represents

Mashcka [7]

I think the answer is C and D..searched it up

3 0

4 years ago

Read 2 more answers

The expression -5p+20 factored

Nutka1998 [239]

Ok I’ve attached a photo