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vazorg [7]
3 years ago
7

Pls help this is a test plss i need it

Mathematics
1 answer:
sashaice [31]3 years ago
5 0

Answer:

B

Step-by-step explanation:

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A high-speed train traveled 2200 miles in 10 hours without making any stops through the countryside of a rural area of southern
algol13
Speed = distance / time

speed = 2200/10
speed = 220 miles per hr


4 0
3 years ago
Solve for x: 4(x-5) 8. = 9y​
lora16 [44]

Answer:

X=18y+5

EXPLANATION

4(X-5)/8 =9Y

(4X-20)/8 =9Y

4X-20=9Y×8

4X=72Y+20

X=(72Y+20)/4

X=18Y+5

8 0
2 years ago
Use single digits times a power of 10 to estimate the number 0.00005423
VashaNatasha [74]

Answer:   5.423 × 10^-5

4 0
4 years ago
At a carry-out pizza restaurant, an order of 3 slices of pizza, 4 breadsticks, and 2 juice drinks costs $13.35. A second order o
BartSMP [9]

Answer: Pizza = $2.95, Breadstick = $0.50, Juice = $1.25

<u>Step-by-step explanation:</u>

Let P represent the cost of a slice of pizza

and B represent the cost of breadstick

and J represent the cost of a juice drink.

EQ1: 3P + 4B + 2J = 13.35

EQ2: 5P + 2B + 3J = 19.50

EQ3: 4B + J = P + 0.30     -->     P - 4B - J = -0.30

Let's eliminate B from EQ1 and EQ2 to form EQ4:

3P + 4B + 2J = 13.35   →  1(3P + 4B + 2J = 13.35)   →   3P + 4B + 2J =  13.35

5P + 2B + 3J = 19.50  → -2(5P + 2B + 3J = 19.50)  →  <u>-10P -  4B -  6J</u> = <u>-39.00</u>

                                                                        EQ4:     -7P          -4J    = -25.65

And eliminate B from EQ1 and EQ3 to form EQ5:

               3P + 4B + 2J = 13.35  

             <u>    P -  4B  - J </u> =<u> -0.30</u>

EQ5:       4P           + J  = 13.05    

Now, eliminate J from EQ4 and EQ5 to solve for P:

-7P  - 4J = -25.65  →    1(-7P  - 4J = -25.65)   →   -7P  - 4J = -25.65

 4P  +  J = 13.05   →    4(4P  +   J =  13.05)    →  <u>  16P  +4J </u>=  <u>52.20</u>

                                                                             9P          = 26.55

                                                                           <u>÷9   </u>           <u>÷9     </u>

                                                                                    P = 2.95

Plug in P = 2.95 into EQ4 or EQ5 to solve for J:

EQ5: 4P + J = 13.05

        4(2.95) + J = 13.05

        11.80 + J = 13.05

                   J = 1.25

Plug in P = 2.95 and J = 1.25 into either EQ1 or EQ2 or EQ3 to solve for B:

EQ3: 4B + J = P + 0.30

        4B + 1.25 = 2.95 + 0.30

        4B + 1.25 = 3.25

                   4B = 2.00

                     B = 0.50

Check (since we used EQ3 to find B, use either EQ1 or EQ2):

EQ2: 5P + 2B + 3J = 19.50

       5(2.95) + 2(0.50) + 3(1.25) = 19.50

       14.75 + 1.00 + 3.75 = 19.50

                            19.50 = 19.50     \checkmark

6 0
3 years ago
What are the solutions of this quadratic equation? X2 − 10x = -34 A. X= -8, -2 B. X= 5 + 3i C. X= -5 + 3i D. X= -5 + square root
MakcuM [25]

Answer:

B. X= 5 + 3i

5 + 3i

Step-by-step explanation:

We are given the quadratic equation

x² - 10x = -34

x² - 10x + 34 = 0

Using Almighty formula

x = -b ± √b² - 4ac/2a

When given equation: ax² + bx + c

Where: a = 1, b = -10 , c = 34

x = -10 ± √-10² - 4 × 1 × 34/2 × 1

x = 10 ± √100 - 136/2

x = 10 ± √-36 /2

x = 10/2 ±. √-36/2

x = 5 ± 6i /2

x = 5 ± 3i

Hence: the roots of the equation are:

x = 5 - 3i , x = 5 + 3i

6 0
3 years ago
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