To solve this problem you must apply the proccedure showb below:
1. You have the following equation:
<span> 2x^2+9y^2=18
2. Dividing the equation by 18, you have:
(x^2/9)+(y^2/2)=1
3. The center is:
[</span>(x-0)^2/9]3^2[(y-0)^2/√2]=1
<span>
(h,k)=(0,0)
The center is (0,0)
4. The vertices are:
a^2=9
a=3
Vertices: (-3,0) and (3,0)
5. The foci is:
c^2=a^2-b^2
c=</span>√7
<span>
The foci is: (-</span>√7,0) and (√7,0)
There are an infinite number of solutions, but some that work are (-2,0), (1,-3), and (0,-6)
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Combine like terms 10x+x=11x
Answer:
The domain is the set of values you put into the function.
The range is the set of values the function outputs.
<u>Example problem</u>:
Find the range of this function: y = 2x + 3, x > 0
The x > 0 part is the domain, so this means that only positive values of x can be inputted in the function.
If only positive values can be inputted in the function, then the range will be: y > 3