The chance that they will have one girl is 1:5 because they are having 5 children and one is going to be a girl
2+5+8+11+14+17+20+23+26+29+32+35
Answer:
I not sure what the question is
Step-by-step explanation:
Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that
P(Ch) = 88/520
P(C) = 76/520
P(Ch and C) = 31/520
and we want to find P(Ch or C).
Using the inclusion/exclusion principle, we have
P(Ch or C) = P(Ch) + P(C) - P(Ch and C)
P(Ch or C) = 88/520 + 76/520 - 31/520
P(Ch or C) = 133/520
