All categories

2 years ago

What does the statement T(20) = T(c) mean?

Mathematics

1 answer:

artcher [175]2 years ago

5 0

It is C. floor 20 and floor c have the same amount of tenants

You might be interested in

Set up an equation to show (×+2)×5=y

Masteriza [31]

5x+10 = y

Subtract 10 from both sides.

5x = y - 10

Divide both sides by 5.

x = 1/5y - 2

Plugin 1/5y - 2 for the y.
5(1/5y - 2)
1 - 10 + 10 = y

1 = y

Your Answer(s)
y = 1
x = 1/5y - 2

4 0

3 years ago

What is the equation of the line that passes through the points (-1 , 3/2) and (1/2 , 1/2 )

Simora [160]

Answer:

y = -2/3x + 5/6 (slope intercept) (y = ax + b)

4x + 6y = 5 (standard form) (Ax + By = C)

y - 3/2 = -2/3(x + 1) (point slope) (y-y1 = m(x-x1)) (m = y2 - y1 / x2 - x1)

______________________________________

6 0

2 years ago

Find the slope and the y-intercept of the line in the graph.

Radda [10]

The slope is 2. The y-intercept is 4.

Explanation:

The line constantly goes up to units for every unit that it goes to the right. The y intercept is 4 because it is 4 on the y-axis when x is 0.

8 0

2 years ago

Read 2 more answers

For which values of k does the system of linear equations have zero, one, or an infinite number of solutions? [Note: not all thr

viktelen [127]

Answer:

The system has an infinite solution at k = 6, otherwise for any value of k, it has zero solution.

Step-by-step explanation:

Consider the system of linear equations:

$3x_{1} -x_{2}=2\;\;\;\;\;\;(1)\\ 9x_{1} -3x_{2}=k\;\;\;\;\;(2)$

The system of linear equations can have zero, one, or an infinite number of solutions:

simplify equation (1):

$x_{2}=3x_{1} -2$

substitute in equation (2), we get

$9x_{1} -3(3x_{1}-2)=k\\9x_{1} -9x_{1}+6=k\\0+6=k$

we cannot find the value of $x_{1}$ and $x_{2}$ .

so, there is no solution.

Multiply the equation (1) with 3 and put k is 6,

$3(3x_{1} -x_{2})=3\times2\\9x_{1} -3x_{2})=6$

it means both equations are overlapped. Then, the solution has infinite solutions.

Hence, the system has an infinite solutions at k is 6 otherwise for any value of k it has no solution.

4 0

2 years ago

Evaluate the limit as x goes to infinity of x^3e^-x/5

jekas [21]

Answer: 0

Step-by-step explanation:

$\frac{x^{3}e^{-x}}{5}$

This could be written as

$\frac{x^{3} }{5e^{-x} }$

Applying L'H rule and differentiating 3 times , we have

$\frac{6}{5e^{x} }$

taking the limit as x goes to infinity , we have

5 0

2 years ago