All categories

3 years ago

What does the statement T(20) = T(c) mean?

Mathematics

1 answer:

artcher [175]3 years ago

5 0

It is C. floor 20 and floor c have the same amount of tenants

You might be interested in

Need help asap...thank you...

Nikolay [14]

Answer:

Lezza did make an error, she also needs to multiply -5 by 3.

Step-by-step explanation:

Lezza needs to use the distrubitive property.

Therefore she needs to distrubute 3 to both 2x and -5

If she had done that, the answer would be

4x=7+6x-15

Which simplifies to 4x= -8+6x

3 0

3 years ago

(1/2)*(1/2) + 2*1/2*1/4 + (1/4)*(1/4) = ____

stiks02 [169]

=1/4+1/4+1/16=8/16+1/16=9/16

3 0

3 years ago

Read 2 more answers

An employee's gross pay for a period is $820. The employee takes one withholding for a state allowance of $19. There is also a s

kondor19780726 [428]

I think the answer is D good luck

4 0

3 years ago

A coin is tossed 20 times. A person, who claims to have extrasensory perception, is asked to predict the outcome of each flip in

Korolek [52]

Answer:

5.77% probability of being correct 14 or more times by guessing

Step-by-step explanation:

For each time the coin is tossed, there are only two possible outcomes. Either the person predicts the correct outcome, or she does not. The probability of predicting the correct outcome in a toss is independent of other tosses. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A coin is tossed 20 times.

This means that $n = 20$

Fair coin:

Equally as likely to be heads or tails, so $p = \frac{1}{2} = 0.5$

What is the probability of being correct 14 or more times by guessing

$P(X \geq 14) = P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 14) = C_{20,14}.(0.5)^{14}.(0.5)^{6} = 0.0370$

$P(X = 15) = C_{20,15}.(0.5)^{15}.(0.5)^{5} = 0.0148$

$P(X = 16) = C_{20,16}.(0.5)^{16}.(0.5)^{4} = 0.0046$

$P(X = 17) = C_{20,17}.(0.5)^{17}.(0.5)^{3} = 0.0011$

$P(X = 18) = C_{20,18}.(0.5)^{18}.(0.5)^{2} = 0.0002$

$P(X = 19) = C_{20,19}.(0.5)^{19}.(0.5)^{1} \approx 0$

$P(X = 20) = C_{20,20}.(0.5)^{20}.(0.5)^{0} \approx 0$

Then

$P(X \geq 14) = P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.0370 + 0.0148 + 0.0046 + 0.0011 + 0.0002 + 0 + 0 = 0.0577$

5.77% probability of being correct 14 or more times by guessing

5 0

3 years ago

Whats the answer? 2 x (–8) x (–9) 19 –19 –144 144

77julia77 [94]

Answer:

Your answer is simply 144

7 0

3 years ago

Read 2 more answers