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saw5 [17]
3 years ago
7

The area of a rhombus is 8.7 cm2. The base of the rhombus is 3 cm. Find the height of the rhombus

Mathematics
2 answers:
Reika [66]3 years ago
8 0

Answer:

area = base \times height \\  8.7 = 3 \times h \\ h =  \frac{8.7}{3}  \\  \\ { \boxed{ \boxed{height = 2.9 \: cm}}}

Blababa [14]3 years ago
7 0

Area=base*height

8.7=3*h

8.7:3=h

2.9=h

Please mark Brainliest!

I wish you luck with Maths!:-)

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Plzzz help i will give brainliest if i can
Alla [95]

Answers: choice C and choice E

Plugging x = 3 and y = -1 into both equations of choice C lead to a true result (the same number on both sides). This is why the system of equations listed in choice C is one possible answer. Choice E is a similar story.

If your teacher didn't mean to make this a "select all that apply" type of problem, then it's likely your teacher may have made a typo.

3 0
3 years ago
Write a equivalent expression for 12a+60
viva [34]

Answer: 12(a+5)

Step-by-step explanation: factor out 12 from the expression

ANSWER 12(a+5)

8 0
3 years ago
Find the slope of the line that passes through the points (2, 1) and (-4, -5).
uysha [10]

the slope of the  is m= 1

5 0
4 years ago
Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the
kodGreya [7K]

Answer:

  • p=0.7103 (4-game series)
  • p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters  n=4, p=0.6:

P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\  i=4,5,6,7

#We find probabilities for the different values of i:

P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659

Hence, probability of the stronger team winning overall is:

=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103

#Define Y as the random variable for winning 2/3 games.:

P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0
3 years ago
The function C (t) = StartFraction 4 t Over t squared + 2 EndFraction models the cost per student of a field trip when x student
choli [55]

Answer:

C. It is vertically stretched by a factor of 200 and shifted 10 units up.

Step-by-step explanation:

<3

7 0
3 years ago
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