This is so provided that the velocity changes continuously in which case we can apply the mean value theorem.
<span>Velocity (v) is the derivative of displacement (x) : </span>
<span>v = dx/dt </span>
<span>Monk 1 arrives after a time t* and Monk 2 too. </span>
<span>Name v1(t) and v2(t) their respective velocities throughout the trajectory. </span>
<span>Then we know that both average velocities were equal : </span>
<span>avg1 = avg2 </span>
<span>and avg = integral ( v(t) , t:0->t*) / t* </span>
<span>so </span>
<span>integral (v1(t), t:0->t*) = integral (v2(t), t:0->t*) </span>
<span>which is the same of saying that the covered distances after t* seconds are the same </span>
<span>=> integral (v1(t) - v2(t) , t:0->t*) = 0 </span>
<span>Thus, name v#(t) = v1(t) - v2(t) , then we obtain </span>
<span>=> integral ( v#(t) , t:0->t*) = 0 </span>
<span>Name the analytical integral of v#(t) = V(t) , then we have </span>
<span>=> V(t*) - V(0) = 0 </span>
<span>=> V(t*) = V(0) </span>
<span>So there exist a c in [0, t*] so that </span>
<span>V'(c) = (V(t*) - V(0)) / (t* - 0) (mean value theorem) </span>
<span>We know that V(0) = V(t*) = 0 (covered distances equal at the start and finish), so we get </span>
<span>V'(c) = v#(c) = v1(c) - v2(c) = 0 </span>
<span>=> v1(c) = v2(c) </span>
<span>So there exist a point c in [0, t*] so that the velocity of monk 1 equals that of monk 2. </span>
Answer:
Step-by-step explanation:
Point-Slope form is: 
'm' - Slope
(x1, y1) - Point Coordinate
We are given the point of (-1,3) and the slope of 5.
Replace 'm' with 5, 'x1' with -1, and 'y1' with 3:
1 out if 20 you would get right
There is 5 questions 4 answers to pick from so 5 times 4 is 20
Then they said what is the probability of only getting one answer right
So the answer would be 1 out of 20 1/20
Answer:
false
Step-by-step explanation:
Answer:
Step-by-step explanation:
The triangle is a right angle triangle. This is because one of its angles is 90 degrees.
Let us determine x
Taking 47 degrees as the reference angle,
x = adjacent side
11 = hypotenuse
Applying trigonometric ratio,
Cos # = adjacent side / hypotenuse
# = 47 degrees
Cos 47 = x/11
x = 11cos47
x = 11 × 0.6820
x = 7.502
Let us determine y
Taking 47 degrees as the reference angle,
y = opposite side
11 = hypotenuse
Applying trigonometric ratio,
Sin # = opposite side / hypotenuse
# = 47 degrees
Sin 47 = y/11
x = 11Sin47
x = 11 × 0.7314
x = 8.0454
