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natta225 [31]
3 years ago
9

The student council is planning the school carnival. Each

Mathematics
1 answer:
Assoli18 [71]3 years ago
5 0

Answer: y = 2.50x

Step-by-step explanation:

X represents the number of tickets sold, and because each ticket costs $2.50, the expression would be 2.50x to find how much money is raised, which can be represented as y.

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Admission to a carnival is $5 and each game at the carnival costs $0.85. You have $15 to spend on admissions and games. What is
Nadusha1986 [10]

Answer: 11 games

Step-by-step explanation:

With $15,

First step, subtract cost of admission= $5

$15 - $5 = $10

If one game costs $0.85

× games = $10/ $0.85

=11.7

The maximum number of games he can play is 11.

I hope this is clear.

3 0
3 years ago
I’m not sure how to figure out what numbers to fill in and the equation
Tanzania [10]
Lets calculate linear equation
assume
y = f(x)= mx +b

now given
f(0) = 2
m×0+b = 2
b = 2
so b = 2
given f(4) = 0.125 = 1/8
m×4 + 2 = 1/8
4m = 1/8-2= -15/8
m = -15 /(8×4) = -15/32

so linear equation is
y = mx + b = -15x/32 + 2


exponential equation is same as you have written

y = 2(0.5)^x

now put values of x in each equation to get value of y

x =0

linear y = -15×0/32+2 = 2

exp y = 2(0.5)^0 = 2×1 = 2

x =1

linear y = -15×1/32+2 = 2-15/32= 49/32

exp y = 2(0.5)^1 = 2×1/2 = 1

x =2

linear y = -15×2/32+2 = 2-30/32= 17/16

exp y = 2(0.5)^2 = 2×1/4 = 0.5

x =3

linear y = -15×3/32+2 = 2-45/32= 19/32

exp y = 2(0.5)^3 = 2×1/8= 0.25

x =4

linear y = -15×4/32+2 = 2-60/32= 4/32 = 0.125

exp y = 2(0.5)^4= 2×1/16 = 1/8= 0.125
8 0
3 years ago
In Circle P, EP = 2, PG = 12, and FP = 4.
Paladinen [302]

Answer:

6

Step-by-step explanation:

FP * PH = GP * EP

If  EP = 2, PG = 12, and FP = 4.

Then 4 * PH = 12 * 2

4 * PH = 12 * 2

step 1 simplify

4 * ph = 4PH

12 * 2 = 24

we now have 4PH = 24

step 2 divide each side by 4

4PH / 4 = PH

24 / 4 = 6

we're left with PH = 6

7 0
3 years ago
Bill bought a $300 watch which was on sale for $280. What was the percent discount?
Nuetrik [128]

I am a little confused on what you meant, and I'm not sure if its correct. I think he saved $20

6 0
2 years ago
good evening! Can someone please answer this, ill give you brainliest and your earning 50 points. Would be very appreciated.
AVprozaik [17]

Answer:

<u>Part 1</u>

Set B

<u>Part 2</u>

We can use the FOIL method to multiply these expressions:

\textsf{FOIL}: \quad(a+b)(c+d)=ac+ad+bc+bd

However, as all the expression are in the format (a+b)^2, we can use the shortcut:  (a+b)^2=a^2+2ab+b^2

<u>Part 3</u>

Using the shortcut to find the products:

\begin{aligned}\implies (x+5)(x+5)& =(x+5)^2\\ & =x^2+2(x)(5)+5^2\\ & =x^2+10x+25\end{aligned}

\begin{aligned}\implies (2x+9)(2x+9) & = (2x+9)^2\\ & = (2x)^2+2(2x)(9)+9^2\\ & = 4x^2+36x+81\end{aligned}

\begin{aligned}\implies (x+1)^2 & = x^2+2(x)(1)+1^2\\ & = x^2+2x+1\end{aligned}

<u>Part 4</u>

A new example of a multiplication problem based on the structure of Set B is:  (3x+2)(3x+2)

\begin{aligned}\implies (3x+2)(3x+2) & = (3x+2)^2\\ & = (3x)^2+2(3x)(2)+2^2\\ & = 9x^2+12x+4\end{aligned}

<u>Part 5</u>

An example of a multiplication problem that would NOT be included in Set B based on its structure is: (x+2)(x-2)

We cannot use the derived Set B shortcut (from part 2) to multiply this expression.  Instead, we would have to use a different shortcut of "The Difference of Two Squares" to find the product of this example expression.

5 0
2 years ago
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