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kondaur [170]
3 years ago
15

Grafica la función y=x^2-6x+9​

Mathematics
1 answer:
KIM [24]3 years ago
5 0

Answer:Recuerda que solo debe haber una variable en la ecuación

Step-by-step explanation:

No sé la respuesta porque estoy aprendiendo sobre este tipo de pregunta hoy, pensé que podría responderla, lo siento pero no puedo

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The domain of this function is {-12,-6,3,15}. Y=-2/3x+7
Evgen [1.6K]

Considering the given function, the table is completed as follows:

x|y

-12|15

-6| 11

3|5

15|-3

<h3>Which is the function?</h3>

The function is defined by:

y = -\frac{2}{3}x + 7

Hence, when x = -12:

y = -\frac{2}{3}(-12) + 7 = 15

When x = -6:

y = -\frac{2}{3}(-6) + 7 = 11

When x = 3:

y = -\frac{2}{3}(3) + 7 = 5

When x = 15:

y = -\frac{2}{3}(15) + 7 = -3

More can be learned about functions at brainly.com/question/25537936

#SPJ1

6 0
2 years ago
Determine whether the statements are True or False. Justify your answer with an explanation.
frez [133]

Problem 1

<h3>Answer: False</h3>

---------------------------------

Explanation:

The notation (f o g)(x) means f( g(x) ). Here g(x) is the inner function.

So,

f(x) = x+1

f( g(x) ) = g(x) + 1 .... replace every x with g(x)

f( g(x) ) = 6x+1 ... plug in g(x) = 6x

(f o g)(x) = 6x+1

Now let's flip things around

g(x) = 6x

g( f(x) ) = 6*( f(x) ) .... replace every x with f(x)

g( f(x) ) = 6(x+1) .... plug in f(x) = x+1

g( f(x) ) = 6x+6

(g o f)(x) = 6x+6

This shows that (f o g)(x) = (g o f)(x)  is a false equation for the given f(x) and g(x) functions.

===============================================

Problem 2

<h3>Answer: True</h3>

---------------------------------

Explanation:

Let's say that g(x) produced a number that wasn't in the domain of f(x). This would mean that f( g(x) ) would be undefined.

For example, let

f(x) = 1/(x+2)

g(x) = -2

The g(x) function will always produce the output -2 regardless of what the input x is. Feeding that -2 output into f(x) leads to 1/(x+2) = 1/(-2+2) = 1/0 which is undefined.

So it's important that the outputs of g(x) line up with the domain of f(x). Outputs of g(x) must be valid inputs of f(x).

7 0
3 years ago
The rate of change is<br><br> A. -4<br> B. -1<br> C. 1<br> D. 4
babymother [125]
The rate of change is 4 so your answer would be D. 4
3 0
3 years ago
What is 2p times p?<br> plz help
natulia [17]

2p*p= 2p^2  because when you multiply p by p it squares it, then you keep the 2 in front of it
4 0
3 years ago
Please help asap I need this for a test and I’m failing
RideAnS [48]

Answer:

perpendicular  bisector

Step-by-step explanation:

sorry if im wrong

3 0
3 years ago
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