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3 years ago

Type "numerator" or "denominator" to complete each statement. x4 is in the . y14 is in the . z4 is in the .

Mathematics

2 answers:

Elena-2011 [213]3 years ago

8 0

Answer:

Step-by-step explanation:

X^4 is in the "Numerator".

Y^14 is in the "Denominator".

Z^4 is in the "Denominator".

I just took the test.

Alex777 [14]3 years ago

3 0

Answer:

numerator

denominator

denominator.

Step-by-step explanation:

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An item is regularly priced at $15. It is now priced at a discount of 55% off the regular price.

Verdich [7]

If it is marked at 55% off, the u r actually paying 45%

so 45% of 15 = 0.45(15) = 6.75 <== discounted price

6 0

3 years ago

Through (1,0) slope = -1

telo118 [61]

Answer:

y = -1x+1

Step-by-step explanation:

The equation for a line in slope intercept form is

y = mx+b where m is the slope and b is the y intercept

y = -1x+b

Substitute in the point

0 = -1(1) +b

0 = -1+b

1 = b

The equation is

y = -1x+1

7 0

3 years ago

PLS HELP WILL MARK BRAINLIEST!

Nikolay [14]

1 container = 5 gallon

The household uses 4 containers that is 20 gallons.

The family uses 20 gallons a week.

1 week = 20 gallons

2.5 weeks = 50 gallons.

1 gal = 3.7584L

50 gallons = 187.92L

The family uses 187.92L in 2.5 weeks.

8 0

3 years ago

A researcher has developed a new drug designed to reduce blood pressure. In an experiment, 21 subjects were assigned randomly to

Paladinen [302]

Answer:

Step-by-step explanation:

Hello!

The objective of the research is to compare the newly designed drug to reduce blood pressure with the standard drug to test if the new one is more effective.

Two randomly selected groups of subjects where determined, one took the standard drug (1- Control) and the second one took the new drug (2-New)

1. Control

X₁: Reduction of the blood pressure of a subject that took the standard drug.

n₁= 23

X[bar]= 18.52

S= 7.15

2. New

X₂: Reduction of the blood pressure of a subject that took the newly designed drug.

n₂= 21

X[bar]₂= 23.48

S₂= 8.01

The parameter of study is the difference between the two population means (no order is specified, I'll use New-Standard) μ₂ - μ₁

Assuming both variables have a normal distribution, there are two options to estimate the difference between the two means using a 95% CI.

1) The population variances are unknown and equal:

[(X[bar]₂-X[bar]₁)± $t_{n_1+n_2-2;1-\alpha /2}$ *( $Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }$ )]

$t_{n_1+n_2-2;1-\alpha /2}= t_{23+21-2;1-0.025}= t_{42;0.975}= 2.018$

$Sa=\sqrt{\frac{(n_1-1)*S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{22*7.15^2+20*8.01^2}{42} }= 7.57$

[23.48-18.52]±2.018*( $7.57*\sqrt{\frac{1}{21} +\frac{1}{23} }$ )]

[0.349; 9.571]

2) The population variables are unknown and different:

Welche's approximation:

[(X[bar]₂-X[bar]₁)± $t_{Dfw;1-\alpha /2}$ *( $\sqrt{\frac{S_1^2}{n_1} +\frac{S_2^2}{n_2} }$ )]

$Df_{w}= \frac{(\frac{S_1^2}{n_1} +\frac{S^2_2}{n_2} )^2}{\frac{(\frac{S_1^2}{n_1} )^2}{n_1-1}+ \frac{(\frac{S_2^2}{n_2} )^2}{n_2-1} } = \frac{(\frac{7.15^2}{23} +\frac{8.01^2_2}{21} )^2}{\frac{(\frac{7.15^2}{21} )^2}{20}+ \frac{(\frac{8.01^2}{23} )^2}{22} } = 42.85= 42$

$t_{Df_w;1-\alpha /2}= t_{42; 0.975}= 2.018$

[(23.48-18.52)±2.018 $\sqrt{\frac{7.15^2}{23} +\frac{8.01^2}{21} }$ ]

[0.324; 9.596]

I hope this helps!

4 0

3 years ago

For every A earned, Max's parents allowed Max to stay up 15 minutes later. Max's normal bedtime was 8:30.

babymother [125]

A. 2 A's
B. 4 A's
C. 8:00

3 0

3 years ago