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2 years ago

Anyone know the answer?

Mathematics

1 answer:

Alika [10]2 years ago

7 0

Well if you notice, 48, x, and x are all on the same line, so they must add up to equal 180 degrees. So...

2x + 48 = 180
2x = 132
x = 66

So each x is equal to 66 degrees. Now we know the triangle is a right triangle, and the sum of all interior angles must be equal to 180 degrees for a triangle. So...

66 + 90 + z = 180
156 + z = 180
z = 24

Z equals 24 degrees! I hope this helps!

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I need help ASAP , so what’s the answer

aivan3 [116]

The answer would be A.) 1

To find this answer you solve for x. Subtract 3/2 from both sides. This will give you 1/2x = 1/2^x. Then, divide by 1/2 on both sides to get x = 1.

To check this fill in x with 1. Then solve.

1/2 * 1/1 + 3/2 = 2^1
1/2 + 3/2 = 2
4/2 = 2
2 = 2

Thus making 1 the answer. Here's an image to show how I got this. I hope this helps!

6 0

3 years ago

A meter stick casts a shadow 2.4 m long at the same time a flagpole casts a shadow 9.7 m long. How tall is the flagpole

Luda [366]

The first thing we are going to do is draw a diagram of the situation to help us to solve the situation.
We an draw tow similar triangle between the length of the shadows and the height of the stick and the pole.
Since <span>meter stick has a length of 1 meter, the height of our smaller triangle is 1 meter. Let </span> $h$ be height of of the pole. Since both triangles are similiar we can establish a proportion between their corresponding sides and solve for $h$ :
$\frac{h}{1} = \frac{9.7}{2.4}$
$h=\frac{9.7}{2.4}$
$h=4.04$

We can conclude that the pole is 4.04 meters tall.

8 0

2 years ago

If a jogger runs 2 miles and burns 185 calories, how many calories would he burn if he jogged 3 miles?

aliina [53]

The total amount of calories burnt in jogging 2 miles = 185 calories

We have to determine the number of calories burned in jogging 3 miles.

Firstly, we will determine the amount of calories burnt in jogging 1 mile. We will use unitary method to evaluate this.

So, the total amount of calories burnt in jogging 1 mile = $185 \div 2$

= 92.5 calories

So, the amount of calories burnt in 3 miles = $3 \times 92.5$

= 277.5 calories

Therefore, 277.5 calories are burned in jogging 3 miles.

6 0

3 years ago

Read 2 more answers

2. Ms. Groves has trays of paints for students in her

olga55 [171]

Answer:

Each tray has 5 colours and one of the colour on the tray is purple. Hence 1/5 of the colours on the tray is purple and thus 1/5 of the colours on the 20 trays is purple. The fraction of colours on the trays will not change. If written out logically, 20 purples out of 100 colours in total on the trays will also given the fraction 1/5.

4 0

3 years ago

Find the equation of an exponential function in the form y = ab^x, given the points (0, 3) and (2, 108/25). Please simplify your

lilavasa [31]

We have the equation:

$y=a\cdot b^x$

We know two points and we will use them to calculate the parameters a and b.

The point (0,3) will let us know a, as b^0=1.

$\begin{gathered} y=a\cdot b^x \\ 3=a\cdot b^0=a \\ a=3 \end{gathered}$

Now, we use the point (2, 108/25) to calcualte b:

$\begin{gathered} y=3\cdot b^x \\ \frac{108}{25}=3\cdot b^2 \\ 3\cdot b^2=\frac{108}{25} \\ b^2=\frac{108}{25\cdot3}=\frac{108}{3}\cdot\frac{1}{25}=\frac{36}{25} \\ b=\sqrt[]{\frac{36}{25}} \\ b=\frac{\sqrt[]{36}}{\sqrt[]{25}} \\ b=\frac{6}{5} \end{gathered}$

Then, we can write the equation as:

$y=3\cdot(\frac{6}{5})^x$

5 0

6 months ago