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emmasim [6.3K]
2 years ago
14

Can someone help me solve this problem!!?

Mathematics
1 answer:
shepuryov [24]2 years ago
5 0
11x+3x=14x-19 you get the 19 from adding 15 and 4 together
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Ples help will mark brainliest if 2 answers.
BabaBlast [244]

Answer:

see below

Step-by-step explanation:

Choose a couple of values for x. Figure out the corresponding values for y. Plot those points and draw a line through them.

Let's choose x=0 and x=4. Then the corresponding y-values are ...

y = 2·0 = 0 . . . . . point (x, y) = (0, 0)

y = 2·4 = 8 . . . . . point (x, y) = (4, 8)

These are graphed below.

7 0
3 years ago
Solve for x:<br> 7x + 5 + x - 3 + x = 5
Soloha48 [4]

Answer:

x=1/3

Step-by-step explanation:

9x+5-3=5

9x=3

x=1/3

6 0
2 years ago
Read 2 more answers
Ronald wants to rent a car to take a trip and has a budget of $60. There is a fixed rental fee of $25 and a daily fee of $5. Wri
Westkost [7]
Daily fee: 5x
rental fee: 25
budget:60

5x + 25 <= 60
7 0
2 years ago
Read 2 more answers
Express the following quantities as ordinary decimal numbers: (step by step please)
jenyasd209 [6]

Answer:

a. 0.0000009 m

b. 6,130, 000, 000

c. 100,000 light years

d. 0.00001 mm

e. 0.0000010 kg

Step-by-step explanation:

Here, we want to come from the standard form to the decimal form

In doing this, we consider the power of 10 attached

If negative, we count leftwards, if positive, we count right-wards

The number of times we count is the power of 10 attached. The count means we are moving the decimal point

For numbers with out visible decimal point, it is at the back of the most right-ward number

Thus, we have these as;

a. 9 * 10^-7

= 0.0000009 m

b. 6.130 * 10^9

= 6,130, 000, 000

c. 1 * 10^5

= 100,000 light years

d. 1 * 10^-5 mm

= 0.00001 mm

e. 10^-7

= 0.0000010 kg

8 0
3 years ago
Describe a scenario where the function value exists at x=c, but the limit does not exist.
Vikki [24]

The scenario can be described using a piecewise function like:

f(x) = 1/x                  if  x < c.

f(x) = x                    if   x = c

f(x) = 1/(x + 73)       if x > c.

<h3>When the value exists but the limit does not?</h3>

Remember that the limit only exists if the limit from left and the limit from the right give the same value.

Then, we can just define a piecewise function of the form:

f(x) = 1/x                  if  x < c.

f(x) = x                    if   x = c

f(x) = 1/(x + 73)       if x > c.

Clearly, this is not a continuous function.

Notice that:

f(c) = c.\\\\ \lim_{x \to c^{-}} f(x) = 1/c\\\\ \lim_{x \to c^{+}} f(x) = 1/(c + 73)

So the limits from left and right are different, then:

\lim_{x \to c^{}} f(x)

Does not exist.

If you want to learn more about limits:

brainly.com/question/5313449

#SPJ1

6 0
2 years ago
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