Answer:
![Width = 20\ in](https://tex.z-dn.net/?f=Width%20%3D%2020%5C%20in)
![Area = 400\ in^2](https://tex.z-dn.net/?f=Area%20%3D%20400%5C%20in%5E2)
Step-by-step explanation:
Given
See attachment for kite dimension
Required
Determine the width and the area
From the attachment, the height of the kite is:
![Height = 31\ in + 9\ in](https://tex.z-dn.net/?f=Height%20%3D%2031%5C%20in%20%2B%209%5C%20in)
![Height = 40\ in](https://tex.z-dn.net/?f=Height%20%3D%2040%5C%20in)
The width which is half the height is:
![Width = \frac{1}{2} * Height](https://tex.z-dn.net/?f=Width%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2A%20Height)
![Width = \frac{1}{2} * 40\ in](https://tex.z-dn.net/?f=Width%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2A%2040%5C%20in)
![Width = 20\ in](https://tex.z-dn.net/?f=Width%20%3D%2020%5C%20in)
The area is:
![Area = \frac{Height * Width}{2}](https://tex.z-dn.net/?f=Area%20%3D%20%5Cfrac%7BHeight%20%2A%20Width%7D%7B2%7D)
![Area = \frac{40\ in * 20\ in}{2}](https://tex.z-dn.net/?f=Area%20%3D%20%5Cfrac%7B40%5C%20in%20%2A%2020%5C%20in%7D%7B2%7D)
![Area = 40\ in * 10\ in](https://tex.z-dn.net/?f=Area%20%3D%2040%5C%20in%20%2A%2010%5C%20in)
![Area = 400\ in^2](https://tex.z-dn.net/?f=Area%20%3D%20400%5C%20in%5E2)
Answer:
41
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
Answer:
out of
Step-by-step explanation: