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bogdanovich [222]
3 years ago
10

3 (2x+8) = 60 x=____​

Mathematics
2 answers:
Gelneren [198K]3 years ago
6 0

Answer:

x=4/9

Step-by-step explanation:

3(2x+8)=60x

6x+24=60x

6x+24-24=60x-24 -60x

-54x=-24

-54x= -24

x= 4/9

AURORKA [14]3 years ago
3 0
X = 6

Step-by-step Explanation:

(Original problem) 3(2x+8)=60

Multiply 3 to 2x and 8: 6x+24=60

Subtract 24 on both sides of the equation: 6x+24=60
-24 -24
6x=36

Divide both sides by 6: 6x/6 = 36/6

Final result: x = 6
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Hope this helps!
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You're trying to find constants a_0,a_1,a_2 such that \hat y=a_0+a_1\hat x+a_2{\hat x}^2. Equivalently, you're looking for the least-square solution to the following matrix equation.


\underbrace{\begin{bmatrix}1&6&6^2\\1&3&3^2\\\vdots&\vdots&\vdots\\1&9&9^2\end{bmatrix}}_{\mathbf A}\underbrace{\begin{bmatrix}a_0\\a_1\\a_2\end{bmatrix}}_{\mathbf x}=\underbrace{\begin{bmatrix}100\\110\\\vdots\\70\end{bmatrix}}_{\mathbf b}

To solve \mathbf{Ax}=\mathbf b, multiply both sides by the transpose of \mathbf A, which introduces an invertible square matrix on the LHS.

\mathbf{Ax}=\mathbf b\implies\mathbf A^\top\mathbf{Ax}=\mathbf A^\top\mathbf b\implies\mathbf x=(\mathbf A^\top\mathbf A)^{-1}\mathbf A^\top\mathbf b

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\mathbf x=\begin{bmatrix}a_0\\a_1\\a_2\end{bmatrix}\approx\begin{bmatrix}121.119\\-3.786\\-0.175\end{bmatrix}

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4 years ago
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