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3 years ago

Can someone help me please

Mathematics

1 answer:

Lana71 [14]3 years ago

3 0

Answer:

y=2x+5

Step-by-step explanation:

At 0, you sit at 5 dollars. The Y axis is money spent, and the X axis is hours parked.

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ValentinkaMS [17]

The best strategy is to use the tables in this example. The tables will give an exact cost for an exact number of apples or oranges. You can then use these pieces of information to determine which number of apples and oranges will get you closest to $10.

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The double bar graph is also not going to work because the two pieces of information are related, so you would not create a separate bar for the price and the number of apples.

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3 years ago

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vladimir1956 [14]

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4 0

4 years ago

Read 2 more answers

|18-x|, if x<18. Pls help

damaskus [11]

Answer:

I18 - xI such that x < 18.

ok, first let's what happens if x = 18:

I18 - xI = I18 - 18I = 0

So, at the moment we have the condition:

I18 - xI > 0.

now, if x is a really large negative number, suppose, x = -100

I18 + 100I = I118I = 118

So, as x can freely move in the negative range, we can see that I18 - xI can be any positive number, so the only restriction that we have is:

I18 - xI > 0.

This means that the domain is:

D = (-∞, 18)

and the range is:

R = (0, ∞)

3 0

3 years ago

What point on the number line below represents the opposite of -4

Vinvika [58]

X is the opposite of -4

7 0

4 years ago

NEED HELP Find values for a, b, c, and d so that the following matrix product equals the 2X2 identity matrix. Explain or show ho

ehidna [41]

We want to find the values of a, b, c, and d such that the given matrix product is equal to a 2x2 identity matrix. We will solve a system of equations to find:

b = 1
a = -1
c = -2
d = -1

<h3>Presenting the equation:</h3>

Basically, we want to solve:

$\left[\begin{array}{cc}-1&2\\a&1\end{array}\right]*\left[\begin{array}{cc}b&c\\1&d\end{array}\right] = \left[\begin{array}{cc}1&0\\0&1\end{array}\right]$

The matrix product will be:

$\left[\begin{array}{cc}-b + 2&-c + 2d\\a*b + 1&a*c + d\end{array}\right]$

Then we must have:

-b + 2 = 1

This means that:

b = 2 - 1 = 1

b = 1

We also need to have:

a*b + 1 = 0

we know the value of b, so we just have:

a*1 + b = 0

a = -1

Now the two remaining equations are:

-c + 2d = 0

a*c + d = 1

Replacing the value of a we get:

-c + 2d = 0

-c + d = 1

Isolating c in the first equation we get:

c = 2d

Replacing that in the other equation we get:

-(2d) + d = 1

-d = 1

d = -1

Then:

c = 2d = 2*(-1) = -2

c = -2

So the values are:

b = 1
a = -1
c = -2
d = -1

If you want to learn more about systems of equations, you can read:

brainly.com/question/13729904

4 0

3 years ago