Can someone help me please

What is an algebraic expression for each word phase 16 more than a number n

neonofarm [45]

More than is another way to say increase, or add.
The expression is
n + 16

8 0

3 years ago

How do you determine whether to use substitution or elimination. give an example of a system that you would solve using each met

nadezda [96]

You determine which one to use by seeing which one would be easier

elimination: 5x + 7y = 2
-5x + 6y = 6

substitution: y = 9x + 5
2y = 7x + 2

3 0

3 years ago

on the following unit circle, \thetaθtheta is in radians. a unit circle with an angle from the positive x-axis to a ray labeled

dangina [55]

The value of the trigonometry are sin(Π-Ɵ) = 0.84 and sin(Π + Ɵ) = -0.84

According to the question, there is a circle whose radius is 1 and the ray intersects the circle at point (0.54, 0.84).

We need to find the trigonometric values, that is

sin(Π-Ɵ) = sin(Ɵ) as we know that when the angle is in third quadrant sin is positive.

sin(Π+Ɵ) = -sin(Ɵ) as we know that when the angle is in fourth quadrant sin is negative.

Also note that, sinƟ = perpendicular/hypotenuse

Perpendicular = 0.84 as the perpendicular length will be equal to the length of the y-axis

Hypotenuse = 1 as the hypotenuse will be the radius of the circle which is formed by the ray.

Thus, sinƟ = 0.84/1 = 0.84

Hence, sin(Π-Ɵ) = 0.84

And sin(Π+Ɵ) = -0.84

Learn more about trigonometry here : brainly.com/question/13729598

#SPJ4

5 0

1 year ago

Explain why each of the following integrals is improper. (a) 4 x x − 3 dx 3 Since the integral has an infinite interval of integ

erma4kov [3.2K]

Answer:

a

Since the integral has an infinite discontinuity, it is a Type 2 improper integral

b

Since the integral has an infinite interval of integration, it is a Type 1 improper integral

c

Since the integral has an infinite interval of integration, it is a Type 1 improper integral

d

Since the integral has an infinite discontinuity, it is a Type 2 improper integral

Step-by-step explanation:

Considering a

$\int\limits^4_3 {\frac{x}{x- 3} } \, dx$

Looking at this we that at x = 3 this integral will be infinitely discontinuous

Considering b

$\int\limits^{\infty}_0 {\frac{1}{1 + x^3} } \, dx$

Looking at this integral we see that the interval is between $0 \ and \ \infty$ which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral

Considering c

$\int\limits^{\infty}_{- \infty} {x^2 e^{-x^2}} \, dx$

Looking at this integral we see that the interval is between $-\infty \ and \ \infty$ which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral

Considering d

$\int\limits^{\frac{\pi}{4} }_0 {cot (x)} \, dx$

Looking at the integral we see that at x = 0 cot (0) will be infinity hence the integral has an infinite discontinuity , so it is a Type 2 improper integral

7 0

3 years ago

Can someone please answer this! I will give BRAINLIEST for the best answer I get. The photo below has the question, so please an

Nadya [2.5K]

Answer:

453.73cm³

Step-by-step explanation:

V

=

π

r

2

h

3

3.14×8.5²×6/3=453.73

5 0

3 years ago