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3 years ago

Please help with this

Mathematics

1 answer:

Bingel [31]3 years ago

8 0

D= {5,6,7,8}
R= {0,-2,10,-3}
Function? Yes, the relation is a function.

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The mass of the boulder is 48,567 kilograms. what is the mass of the boulder in metric tons

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1 KG = .001 metric tons. Move the decimal point over three to make it 48.567 metric tons.

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3 years ago

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I need help with this question please!

otez555 [7]

Answer:

B 3.78 seconds

Step-by-step explanation:

On the graph, the line ends when it hits (0,3.78) This means that the object was in the air for 3.78 seconds before hitting the ground (0 height)

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Jasmine filled her bag with 12 strawberries. George filled his bag with 6 times as many strawberries as jasmine. How many strawb

Brilliant_brown [7]

Answer:

There are <u>72 strawberries</u> in George's bag.

Step-by-step explanation:

Given:

Jasmine filled her bag with 12 strawberries. George filled his bag with 6 times as many strawberries as jasmine.

Now, to find the number of strawberries are in George's bag.

Number of strawberries in Jasmine bag = 12.

George filled his bag with 6 times as many strawberries as jasmine.

So, number of strawberries of George's bag is:

$12\times 6$

$=72.$

Therefore, there are 72 strawberries in George's bag.

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2 years ago

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Find the interval(s) where the function is increasing and the interval(s) where it is decreasing. (Enter your answers using inte

Mashcka [7]

Answer:

f'(x) > 0 on $(-\infty ,\frac{1}{e})$ and f'(x)<0 on $(\frac{1}{e},\infty)$

Step-by-step explanation:

1) To find and interval where any given function is increasing, the first derivative of its function must be greater than zero:

$f'(x)>0$

To find its decreasing interval :

$f'(x)$

2) Then let's find the critical point of this function:

$f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}[6-2^{2x}]=\frac{\mathrm{d} }{\mathrm{d}x}[6]-\frac{\mathrm{d}}{\mathrm{d}x}[2^{2x}]=0-[ln(2)*2^{2x}*\frac{\mathrm{d}}{\mathrm{d}x}[2x]=-ln(2)*2^{2x}*2=-ln2*2^{2x+1\Rightarrow }f'(x)=-ln(2)*2^{2x}*2\\-ln(2)*2^{2x+1}=-2x^{2x}(ln(x)+1)=0$

2.2 Solving for x this equation, this will lead us to one critical point since x' is not defined for Real set, and x'' $=\frac{1}{e}$ ≈0.37 for e≈2.72

$x^{2x}=0 \ni \mathbb{R}\\(ln(x)+1)=0\Rightarrow ln(x)=-1\Rightarrow x=e^{-1}\Rightarrow x\approx 2.72^{-1}x\approx 0.37$

3) Finally, check it out the critical point, i.e. f'(x) >0 and below f'(x)<0.

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3 years ago

Suppose you have $16,000 to invest in three stocks, A, B, and C. Stock A is a low-risk stock that has expected returns of 4%. St

podryga [215]

To solve this problem, let us say that:

money invested in stock A = A

money invested in stock B = B

money invested in stock C = C

The given problem states that:

C = A * (1 / 4) = 0.25 A

B = A * (1 / 2) = 0.50 A

It was stated that we only have $16,000 to invest. Therefore:

A + B + C = 16,000

Substituting values of C and B in terms of A:

A + 0.50 A + 0.25 A = 16,000

1.75 A = 16,000

A = $9,142.86

So C and B is:

C = 0.25 (9142.86)
C = $2285.71

B = 0.50 (9142.86)

B = $4571.43

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