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3 years ago

find the equation of a line that is parallel to the straight line 2x-y=-3 and crosses the x-axis at x=-5

Mathematics

1 answer:

Alecsey [184]3 years ago

7 0

Answer:

y=2x+10

Step-by-step explanation:

In line equations its helpful to write your line in the form y = ax + b. This helps because a is always the gadient of the line and b is always the y intercept.

In this case it is y=2x+3

All parallel lines have the same gradient. The gradient of this line = 2.

If the line crosses the x axis at x=-5, then when x =-5 y = 0.

If you put all this in the form y =ax + b you get 0 = 2(-5) +b

So all you need to do to find b is rearrange. b = 10.

Therefore your line has gradient 2 and y intercept 10.

y = 2x + 10

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3 years ago

Find the diameter of a cicle with an area of 240.48 π square millimeters?

seropon [69]

31.02 mm.

Step-by-step explanation:

Step 1:

The area of the given circle is 240.48 π sq mm

We need to find the diameter of the circle

Step 2:

The formula for obtaining the area of any circle is π*r² where r represents the radius of the circle

We know that the diameter of circle is 2 times its radius.

Hence equating the formula of the area of the circle to the given value we can find its radius. Then multiplying the radius by 2 , we get the diameter.

Step 3 :

Using the above method , we have

πr² = 240.48 π

=> r² = 240.48 π / π = 240.48

=> r = √240.48 = 15.51 approximately

Hence the diameter of the given circle is 2 * 15.51 = 31.02 mm.

6 0

3 years ago

PLEASE!!!!!!!The adjoining figure shows two circles with the same center. The

Nookie1986 [14]

<h3>Answer:</h3>

$\boxed{\boxed{\pink{\sf \leadsto Hence \ the \ area \ of \ shaded \ region \ is 264 cm^2}}}$

<h3>Step-by-step explanation:</h3>

Here , two circles are given which are concentric. The radius of larger circle is 10cm and that of smaller circle is 4cm . And we need to find thelarea of shaded region.

From the figure it's clear that the area of shaded region will be the difference of areas of two circles.

Let the,

Radius of smaller circle be r .
Radius of smaller circle be r .
Area of shaded region be $\bf Area_{shaded}$

$\bf \implies Area_{Shaded}= Area_{bigger}-Area_{smaller} \\\\\bf\implies Area_{Shaded} = \pi R^2 - \pi r^2 \\\\\bf\implies Area_{shaded} = \pi ( R^2-r^2) \\\\\bf\implies Area_{shaded} = \pi [ (10cm)^2 - (4cm)^2] \\\\\bf\implies Area_{shaded} = \pi [ 100cm^2-16cm^2] \\\\\bf\implies Area_{shaded} = \pi \times 84cm^2 \\\\\bf\implies Area_{shaded} = \dfrac{22}{7}\times 84cm^2 \\\\\bf\implies \boxed{\red{\bf Area_{shaded} = 264 cm^2 }}$