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3 years ago

Please help meeeee I don’t really understand it

Mathematics

1 answer:

vredina [299]3 years ago

7 0

3*3+4*4=x*x and 9+16=25 so x is 5 and then add other sides so 5+8+4+5

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What would be 82% of 50

MrRissso [65]

10% = 5
80% = 40
2% = 1
82% = 41

41

5 0

3 years ago

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Pumping stations deliver oil at the rate modeled by the function D, given by d of t equals the quotient of 5 times t and the qua

goblinko [34]

<h2>Hello!</h2>

The answer is: There is a total of 5.797 gallons pumped during the given period.

To solve this equation, we need to integrate the function at the given period (from t=0 to t=4)

The given function is:

$D(t)=\frac{5t}{1+3t}$

So, the integral will be:

$\int\limits^4_0 {\frac{5t}{1+3t}} \ dx$

So, integrating we have:

$\int\limits^4_0 {\frac{5t}{1+3t}} \ dt=5\int\limits^4_0 {\frac{t}{1+3t}} \ dx$

Performing a change of variable, we have:

$1+t=u\\du=1+3t=3dt\\x=\frac{u-1}{3}$

Then, substituting, we have:

$\frac{5}{3}*\frac{1}{3}\int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du\\\\\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u}{u} -\frac{1}{u } \ du$

$\frac{5}{9} \int\limits^4_0 {(\frac{u}{u} -\frac{1}{u } )\ du=\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u } )$

$\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u })\ du=\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du$

$\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du=\frac{5}{9} (u-lnu)/[0,4]$

Reverting the change of variable, we have:

$\frac{5}{9} (u-lnu)/[0,4]=\frac{5}{9}((1+3t)-ln(1+3t))/[0,4]$

Then, evaluating we have:

$\frac{5}{9}((1+3t)-ln(1+3t))[0,4]=(\frac{5}{9}((1+3(4)-ln(1+3(4)))-(\frac{5}{9}((1+3(0)-ln(1+3(0)))=\frac{5}{9}(10.435)-\frac{5}{9}(1)=5.797$

So, there is a total of 5.797 gallons pumped during the given period.

Have a nice day!

4 0

3 years ago

20 POINTS FOR BRAINLIEST!! The graph shows Marc's individual and cumulative tips for 7 days Which day gave Marc the sharpest boo

Norma-Jean [14]

The answer is Day 3. The blue bar for day 3 is the tallest, which means that was the highest amount.

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2 years ago

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What is the comparison of two different quantities that are changing

Novosadov [1.4K]

Answer:

Rate of change

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What is 2/300 as a percent

Alecsey [184]

The problem consists in changing a fraction to percent form, a percent is a quantity divided by 100, for example, 50% is equal to 50/100, so lets modify the fraction for it to have 100 as denominator.
so we divide the numerator and denominator by the same number so the fraction does not alterate, keeps being equivalent that is:
2/300
we need to divide the numerator and denominator by 3:
<span>2/300 = (2/3)/(300/3)
</span>= (2/3)/100
now we have it, 2/300 as percent is (2/3)% = 0.67%

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3 years ago

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