Ok I got 32.995 I’m not sure what place you need to round to so I kept that throughout my solving process. I’m not too sure if this is right but here is the work that I did in the picture. I didn’t show the distance formula as I used an online calculator lol.
Answer:
Using the congruency statement, select which statements are true.
Triangle W X Y is congruent to triangle E F G.
Segment W X is congruent to segment F G
Segment W Y is congruent to segment E G
Angle X is congruent to angle F
Angle G is congruent to angle W
Step-by-step explanation:
<h2>Answer is B </h2>
The answer in bold letters. I just tool the test.
Answer:
The LCM of 5 and 12 is 60.
Find the prime factorization of 5
5 = 5
Find the prime factorization of 12
12 = 2 × 2 × 3
Multiply each factor the greater number of times it occurs in steps
LCM = 2 × 2 × 3 × 5
LCM = 60
Answer:
6.68% of students from this school earn scores that satisfy the admission requirement
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 1504, \sigma = 300](https://tex.z-dn.net/?f=%5Cmu%20%3D%201504%2C%20%5Csigma%20%3D%20300)
The local college includes a minimum score of 1954 in its admission requirements. What percentage of students from this school earn scores that satisfy the admission requirement
This is 1 subtracted by the pvalue of Z when X = 1954. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{1954 - 1504}{300}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B1954%20-%201504%7D%7B300%7D)
![Z = 1.5](https://tex.z-dn.net/?f=Z%20%3D%201.5)
has a pvalue of 0.9332
1 - 0.9332 = 0.0668
6.68% of students from this school earn scores that satisfy the admission requirement
I don't understand your question
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