Given that
the weight of football players is distributed with a mean of 200 pounds and a standard deviation of 25 pounds.
And we need to find What is the minimum weight of the middle 95% of the players?
Explanation -
Using the Empirical Rule, 95% of the distribution will fall within 2 times of the standard deviation from the mean.
Two standard deviations = 2 x 25 pounds = 50 pounds
So the minimum weight = 200 pounds - 50 pounds = 150 pounds
Hence the final answer is 150 pounds.
Answer:
z=16
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
−7(z−6)=−70
(−7)(z)+(−7)(−6)=−70(Distribute)
−7z+42=−70
Step 2: Subtract 42 from both sides.
−7z+42−42=−70−42
−7z=−112
Step 3: Divide both sides by -7.
−7z
/−7
=
−112
/−7
z=16
Answer:
0.0838 (8.62%)
Step-by-step explanation:
defining the event G= an out-of-state transaction took place in a gasoline station , then the probability is
P(G) = probability that the transaction is fraudulent * probability that took place in a gasoline station given that is fraudulent + probability that the transaction is not fraudulent * probability that took place in a gasoline station given that is not fraudulent = 0.033 * 0.092 + 0.977 * 0.034 = 0.0362
then we use the theorem of Bayes for conditional probability. Defining also the event F= the transaction is fraudulent , then
P(F/G)=P(F∩G)/P(G) = 0.033 * 0.092 /0.0362 = 0.0838 (8.62%)
where
P(F∩G)= probability that the transaction is fraudulent and took place in a gasoline station
P(F/G)= probability that the transaction is fraudulent given that it took place in a gasoline station
The nth term is 26 because each number is being added by 3. for example: 2+3=5, 5+3=8, etc.
Answer:
Step-by-step explanation:
sinθ = 63/√(16² + 63²) = 63/65
cosθ = 16/65
