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vredina [299]
3 years ago
15

What is the greatest value in the range of f(x) = x2 - 3 for the domain (-3, 0, 1, 2)?

Mathematics
1 answer:
Anettt [7]3 years ago
7 0
Plug in the domain in the equation:
f(-3)=(-3)^2-3=6
f(0)=-3
f(1) = -2
f(2)=1
Range{6,-3,-3,1}
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aleksklad [387]
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eimsori [14]

\longrightarrow{\green{- 9 {x}^{2}   +  14x + 16}} 

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

\sqrt{49}  + [ \sqrt{81} - x \: (9x   -  14) ] \\ \\   =  \sqrt{7 \times 7}  + [ \sqrt{9 \times 9}   - 9 {x}^{2}   +  14x] \\  \\  =  \sqrt{( {7})^{2} }  + [ \sqrt{ ({9})^{2} }  - 9 {x}^{2}  +  14x ] \\  \\  (∵ \sqrt{ ({x})^{2} } = x ) \\  \\  = 7 + (9 - 9 {x}^{2}   + 14x) \\  \\  = 7 + 9 - 9 {x}^{2}   + 14x \\  \\  =  - 9 {x}^{2}   +  14x + 16

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}

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