You would have to replace f(x) with zero and use quadratic formula
f(x)=x^2-5x+5
0=x^2-5x+5
=(-b+-√b^2-4ac)/2a
=(5+-√25-4(1)(5))/2
=(5+-√5)/2
x=(5+√5)/2 or x=(5-√5)/2
Both x values are completely applicable in the equation.
Hope I helped :)
4.054 = 4054/1000 = 2027/500
so I think u you divide something and you times and then you multiply it
Answer:
49m/s
59.07 m/s
Step-by-step explanation:
Given that :
Distance (s) = 178 m
Acceleration due to gravity (a) = g(downward) = 9.8m/s²
Velocity (V) after 5 seconds ;
The initial velocity (u) = 0
Using the relation :
v = u + at
Where ; t = Time = 5 seconds ; a = 9.8m/s²
v = 0 + 9.8(5)
v = 0 + 49
V = 49 m/s
Hence, velocity after 5 seconds = 49m/s
b) How fast is the ball traveling when it hits the ground?
V² = u² + 2as
Where s = height = 178m
V² = 0 + 2(9.8)(178)
V² = 0 + 3488.8
V² = 3488.8
V = √3488.8
V = 59.07 m/s
X²-9x=36
minus 36 both sides
x²-9x-36=0
what 2 numbers multiply to -36 and add to -9
-12 and 3
(x-12)(x+3)=0
set to zero
x-12=0
x=12
x+3=0
x=-3
the number is either -3 or 12
