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4 years ago

The ____ axis is vertical.

Mathematics

2 answers:

4vir4ik [10]4 years ago

6 0

Answer:

Step-by-step explanation:

The y-axis is the the secondary or vertical axis of a system of coordinates, points along which have a value of zero for all other coordinates.

Contact [7]4 years ago

6 0

Answer:

The Y Axis is vertical

Explanation:

The coordinates of a graph are (x,y)

X= Horizontal Line

And

Y= Vertical Line

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An open rectangular box with a square bottom must have a surface area of A square inches. Write a formula for the volume of the

skelet666 [1.2K]

The surface area of the box is being referred to as A
The surface area will be the sum of the four rectangular sides' areas and the base area.
Base area = x²
Rectangular side area = xh
A = x² + 4xh
Volume is, as you said,
V = x²h
Lets substitute h from the formula of A to obtain A in our final answer. Substituting x is possible, but more difficult
(A - x²)/4x = h
V = (x²) * (A - x²)/4x
V = (Ax - x³)/4

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4 years ago

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Ajar contains 6 chocolate chip cookies and 9 peanut butter cookies. Richard grabs 3 cookies at random to pack in his lunch.

mel-nik [20]

Answer: 20%

Step-by-step explanation:

There are 15 total cookies. Divide 3 by 15, 3 being how many cookies he took out. Then you get 0.2. Move the decimal over two and you have 20%.

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3 years ago

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3 years ago

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What binomial do you have to add to the polynomial:

marshall27 [118]

Answer:

a) $-2x^2+5xy$

b) $-3y^2+5xy$

Step-by-step explanation:

Given polynomial : $2x^2+3y^2-5xy+1$

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable x is:

$-2x^2+5xy$

$(2x^2+3y^2-5xy+1)+(-2x^2+5xy)$

$=2x^2+3y^2-5xy+1-2x^2+5xy$

$=2x^2-2x^2+3y^2-5xy+5xy+1$

$=3y^2+1$

Given polynomial : $2x^2+3y^2-5xy+1$

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable y is:

$-3y^2+5xy$

$(2x^2+3y^2-5xy+1)+(-3y^2+5xy)$

$=2x^2+3y^2-5xy+1-3y^2+5xy$

$=2x^2+3y^2-3y^2-5xy+5xy+1$

$=2x^2+1$

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3 years ago

Darla found that the least common denominator needed to subtract \frac{x}{x^2+4x-12}-\frac{3}{x+6}is (x + 6)(x – 2). Which is th

Leona [35]

<h3>Answer: Choice B</h3>

$\frac{x}{(x+6)(x-2)} - \frac{3(x-2)}{(x+6)(x-2)}$

which is the same as x/((x+6)(x-2)) - 3(x-2)/((x+6)(x-2))

=====================================

Explanation:

The LCD is (x+6)(x-2) which is the factorization of x^2+4x-12, and that is the denominator of the first fraction. The first fraction has the LCD already. The second fraction does not. It has (x+6) but it is missing (x-2).

We multiply top and bottom of the second fraction by (x-2) to get the second fraction to have the LCD.

$\frac{3}{x+6}$ turns into $\frac{3}{x+6}*\frac{x-2}{x-2} = \frac{3(x-2)}{(x+6)(x-2)}$