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2 years ago

The vertex form of the equation of a parabola is y = (x - 3)2 + 36.

Mathematics

1 answer:

Nastasia [14]2 years ago

5 0

Answer:

Step-by-step explanation:

y=(x-3)2+36

y=2x+6x+36

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find the equation of the line that is perpendicular to the given line and passes through the given point. CD; (-2,1). C cornet p

Studentka2010 [4]

Answer:

x -2y = -4

Step-by-step explanation:

The slope of the line between points C and D is ...

m = (y2 -y1)/(x2 -x1)

m = (7 -13)/(5 -2) = -6/3 = -2

The slope of the perpendicular line is the opposite reciprocal of this: -1/(-2) = 1/2. The point-slope equation of the desired line is ...

y -k = m(x -h) . . . . line with slope m through point (h, k)

y -1 = 1/2(x -(-2))

We can rearrange this to standard form.

2y -2 = x +2 . . . . . multiply by 2

-4 = x -2y . . . . . . . subtract 2y+2

x -2y = -4 . . . . . . standard form equation of the desired line

5 0

2 years ago

A line passes through point A(10,15). A second point on the line has an x-value that is 125% of the x-value of point A and a y-v

melisa1 [442]

The equation of the line in the point-slope form is y - 15 = $-\frac{3}{2}$ (x - 10)

Step-by-step explanation:

The point-slope form of a linear equation is $y-y_{1}=m(x-x_{1})$ , where

m is the slope of the line, where $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ , $(x_{1},y_{1})$ and $(x_{2},y_{2})$ are two points on the line
$(x_{1},y_{1})$ is a point on the line

∵ Point A = (10 , 15)

∵ The x-coordinate of the second point is 125% of x-coordinate

of point A

∴ x-coordinate of second point = $\frac{125}{100}$ × 10

∴ x-coordinate of second point = 12.5

∵ The y-coordinate of the second point is 75% of y-coordinate

of point A

∴ y-coordinate of second point = $\frac{75}{100}$ × 15

∴ y-coordinate of second point = 11.25

∴ The coordinates of the second point are (12.5 , 11.25)

Let us find the slope of the line by using the rule of it above

∵ $(x_{1},y_{1})$ = (10 , 15)

∵ $(x_{2},y_{2})$ = (12.5 , 11.25)

∴ $m=\frac{11.25-15}{12.5-10}=\frac{-3.75}{2.5}=-\frac{3}{2}$

Now we can write the equation

∵ The point-slope form is $y-y_{1}=m(x-x_{1})$

∵ $m=-\frac{3}{2}$

∵ $(x_{1},y_{1})$ = (10 , 15)

- Substitute these values in the form of the equation

∴ y - 15 = $-\frac{3}{2}$ (x - 10)

The equation of the line in the point-slope form is y - 15 = $-\frac{3}{2}$ (x - 10)

Learn more:

You can learn more about the linear equation in brainly.com/question/4152194

#LearnwithBrainly

5 0

3 years ago

-2=k. 2 = k·1=k<br> Solve the equation.<br> Enter your answer in the box.<br> k=

Gekata [30.6K]

Answer:

k=-1

Step-by-step explanation:

-2=k. 2

Diving whole equation by 2

-2/2=k

k=-1

5 0

3 years ago

Witch is taller 5'3" or 62 inches?

lys-0071 [83]

5,3..........................................

4 0

3 years ago

Read 2 more answers

-4x+2(x-3)>4x-(3+5x)-7

Archy [21]

I hope this helps you

5 0

3 years ago