see the attached figure to better understand the problem
Let
2L---------> lenght side of hexagon
we know that
in one of those triangles
sin 30=1/2
sin 30=L/hypotenuse
solve for L
L=hypotenuse*sin 30-------->L=( 1 8 √ 3 )*(1 /2)------> L=9√3 units
Find the perimeter
perimeter=(2L)*6--------> L*12-------> Perimeter=9√3*12--------->108√3 units
therefore
the answer is
the perimeter of the regular hexagon is 108√3 units
Answer:
Vales of a =3 and b = 6
Step-by-step explanation:
Given that:
.....[1] where a and b are positive integers
we can write 81 and 24 as;


We have [1] as;

Using power rules;

which implies a = b
then;


On comparing both sides we have;
a = 3 and

⇒
Therefore, the value of a and b are, 3 and 6
Answer:
B
Step-by-step explanation:
B-aby you got the stuff