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inna [77]
3 years ago
13

A sporting event held at a high school had 135

Mathematics
2 answers:
Anastaziya [24]3 years ago
6 0
911 is the key of power of mind
vovangra [49]3 years ago
4 0
Twenty fiiiiiveeeeeeeeee
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2/5of a number is 80. What is 34of the same number?
Masja [62]

Answer:

150

Step-by-step explanation:

First you have to find what number 80 is 2/5 of, to do this do the reciprocal of 2/5 which would be 5/2. Multiply 80 by 5/2 and you'll get 200, then find what 3/4 of 200. Multiply 200 by 3, then divide by 4 to get the answer of 150.

3 0
3 years ago
Please help me I tried to do it
anyanavicka [17]
You do 9x27=243 then take 2x31=62 add 243+62=305 then take 305 and subtract it from 28 305-28=277 
so if i did it right you should get n=277
8 0
3 years ago
The data in the chart shows the maximum and corresponding resting heart rate of a healthy 20 year old man. Fit a regression line
lisabon 2012 [21]

Answer:

Can you teach me coeffeicients please honestly like you I need help on the

question to I don't blame you for having trouble on this questions

6 0
4 years ago
Explain how you can use doubles when multiplying with 4 to find 4x8
hoa [83]
When multiplying by 4, you can simply multiply it by 2 twice (prime factorization).
In this example-
4 times 8 = 32
2 times 2 times 8 = 32

Hope this helped!
By the way, I'm getting closer to leveling up, so if you liked my answer, you could reward me with brainliest answer. That'd be great!
8 0
3 years ago
Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discha
mr Goodwill [35]

Answer:

Step-by-step explanation:

Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discharging hot water into the river is given by

T(x) = 160-0.05x^2

a. [0, 10]

For x = 0

T(0) = 160 - 0.05 × 0^2

T(0) = 160

For x = 10

T(10) = 160 - 0.05 × 10^2

T(10) = 160 - 5 = 155

The average temperature

= (160 + 155)/2 = 157.5

b. [10, 40]

For x = 10

T(10) = 160 - 0.05 × 10^2

T(10) = 160 - 5 = 155

For x = 40

T(10) = 160 - 0.05 × 40^2

T(10) = 160 - 80 = 80

The average temperature

= (80 + 155)/2 = 117.5

c. [0, 40]

For x = 0

T(0) = 160 - 0.05 × 0^2

T(0) = 160

For x = 40

T(10) = 160 - 0.05 × 40^2

T(10) = 160 - 80 = 80

The average temperature

= (160 + 80)/2 = 120

6 0
3 years ago
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