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3 years ago

6. In Diagram 1, NPQRSTUV is a regular octagon. NVW and STW are straight lines.

Mathematics

1 answer:

Sveta_85 [38]3 years ago

3 0

Answer:

A. 37.5°

Step-by-step explanation:

∠SPT can be considered an inscribed angle in the circumcircle. In that circle, arc ST would have a measure of 360°/8 = 45°. Angle y° is half that measure, so is 22.5°.

The external angles of a regular octagon are 360°/8 = 45°, so that is the measure of angles UTW and UVW. It is also the amount by which reflex angle TUV exceeds 180°.

The sum of the interior angles of quadrilateral TUVW is ...

45° +225° +45° +3x° = 360°

Then 3x° = 45° and x° = 15°.

Then the sum of interest is ...

x° + y° = 15° + 22.5° = 37.5°

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If the diameter of a circle changes from 18 cm to 6 cm, how will the circumference change?

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The circumference when the diameter is 18 = 18pi

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3 years ago

This table shows a value that represents an exponential function what is the average rate of change for this function for the in

aliya0001 [1]

Answer:

Option A is correct, i.e. 12.

Step-by-step explanation:

Given is the table of x&y relationship which represents an exponential function.

The average rate of change for a function can be found using the following formula:-

F_average = { f(b) - f(a) } / (b-a)

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So, F_average = (32-8)/(5-3)

F_average = 24/2 = 12.

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3 years ago

A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot

ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = $(x\times x)$

$=x^2$

The volume of the box is = area of the base × height

$=x^2h$

Therefore,

$x^2h=272$

$\Rightarrow h=\frac{272}{x^2}$

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

$=20x^2$ cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

$=10x^2$ cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

$=4xh\times 1.5$ cents

$=6xh$ cents

Total cost = $(20x^2+10x^2+6xh)$

$=30x^2+6xh$

Let

C $=30x^2+6xh$

Putting the value of h

$C=30x^2+6x\times \frac{272}{x^2}$

$\Rightarrow C=30x^2+\frac{1632}{x}$

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$C'=60x-\frac{1632}{x^2}$

Again differentiating with respect to x

$C''=60+\frac{3264}{x^3}$

Now set C'=0

$60x-\frac{1632}{x^2}=0$

$\Rightarrow 60x=\frac{1632}{x^2}$

$\Rightarrow x^3=\frac{1632}{60}$

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Now $C''|_{x=3}=60+\frac{3264}{3^3}>0$

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is $=\frac{272}{3^2}$

=30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

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goldfiish [28.3K]

Answer:

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Step-by-step explanation:

For steps, use this link:

https://mathsolver.microsoft.com/en/solve-problem/64705%20%60div%20%20386

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