Ok so R=alfonso's rate
w=wind rate=4
d=rt
with wind rate is R+4
agaoins wind rate is R-4
with wind distance is 34
against is 18 miles
time is same
34=(r+4)t
18=(r-4)t
34=(r+4)t
divide both sides by (r+4)
34/(r+4)=t
18=(r-4)t
divide both sides by (r-4)
18/(r-4)=t
18/(r-4)=t
34/(r+4)=t
set equal to each other
18/(r-4)=34/(r+4)
multiply both sides by (r-4)(r+4)
18(r+4)=34(r-4)
distribute
18r+72=34r-136
subtract 18r from both sides
72=16r-136
add 136 to both sides
208=16r
divide both sides by 16
13mph
answer is 13mph with no wind
Answer:
No, 4+5(6t+1) EQUALS 9+30t
And 9+30t Equals 3(3+10t)
Step-by-step explanation:
GCF=3
3(9/3 + 30t/ 3) =
3(3+10t)
And
4+5(6t+1)
4+30t+5
30t+ (4+5)
Simplifying =
30t+9
Answer:
70!km is the right answer
Step-by-step explanation:
The distance between two cities on a map is 3.5 centimeters. the map is uses a scale in which 1 centimeters represents 20 kilometers.
1. simplify 11/5
- 58/10 - 11/5 =0
2. Divide z by 11/5
- 58/10 - 5z/11 =0
3. simplify 29/5
29/5 - 5z/11 =0
4. calculating the least common multiple
4.1 find the least common multiple
the left denominator is: 5
the right deniminator is: 11
least common multiple:55
....
solution z=319/25 = 12.760
