volume of a sphere is 4/3 * PI * r^3
r = 6
r^3 = 6^3 = 216
4/3 * 216 = 288
Volume = 288 PI in^3
Let
The origin of coordinates the tree
r1 = vector position of the child 1.
r2 = vector position of the child 2
Child 1:
r1 = (12i + 12j)
Child 2:
r2 = (-18i + 11j)
The scalar product will be given by:
r1.r2 = ((12) * (- 18)) + ((12) * (11)) = - 84
The scalar product of their net displacements from the tree is -84m ^ 2
Answer:
2(1 - 6x)
Step-by-step explanation:
2-12x
Common factor: 2
Factored equation:
2(1 - 6x)
Answer:
yes
Step-by-step explanation:
Perimeter of the trapezoid = a + c + 2b
58 = a + c + 2b
Average of bases = (a + c)/2
19 = (a + c)/2
a + c = 38
Substituting (a + c) into the first equation:
58 = 38 + 2b
b = 10 in
We also know that:
c = 2b + 7
c = 2(10) + 7
c = 27 in
a + 27 = 38
a = 11 in
a = 11 in; b = 10 in; c = 27 in
