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3 years ago

There are three silver bows for every four red bows in a bag. what is the ratios?

Mathematics

2 answers:

Vinil7 [7]3 years ago

7 0

Answer:

3:4

Step-by-step explanation:

rusak2 [61]3 years ago

4 0

Answer:

3 silver bows/ 4 red bows or 3 silver bows/ 7 bows

Step-by-step explanation:

You might be interested in

Two numbers multiply together to make 8, but add together to make - 6 What are the two numbers?

Greeley [361]

Answer:

-4 and -2

Step-by-step explanation:

First find all the factors of 8, that would be 1 and 8, -1 and -8, 2 and 4, and -2 and -4.

Then, adding the groups of numbers you have should show you what would equal -6. So 1 + 8 = 9, -1 + (-8) = -9, same vice versa, 2 + 4 = 6, -2 + (-4) = -6. So -2 and -4 would be your two numbers.

8 0

3 years ago

The sum of first three terms of a finite geometric series is -7/10 and their product is -1/125. [Hint: Use a/r, a, and ar to rep

Alchen [17]

Ooh, fun

geometric sequences can be represented as
$a_n=a(r)^{n-1}$
so the first 3 terms are
$a_1=a$
$a_2=a(r)$
$a_2=a(r)^2$

the sum is -7/10
$\frac{-7}{10}=a+ar+ar^2$
and their product is -1/125
$\frac{-1}{125}=(a)(ar)(ar^2)=a^3r^3=(ar)^3$

from the 2nd equation we can take the cube root of both sides to get
$\frac{-1}{5}=ar$
note that a=ar/r and ar²=(ar)r
so now rewrite 1st equation as
$\frac{-7}{10}=\frac{ar}{r}+ar+(ar)r$
subsituting -1/5 for ar
$\frac{-7}{10}=\frac{\frac{-1}{5}}{r}+\frac{-1}{5}+(\frac{-1}{5})r$
which simplifies to
$\frac{-7}{10}=\frac{-1}{5r}+\frac{-1}{5}+\frac{-r}{5}$
multiply both sides by 10r
-7r=-2-2r-2r²
add (2r²+2r+2) to both sides
2r²-5r+2=0
solve using quadratic formula
for $ax^2+bx+c=0$
$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$
so
for 2r²-5r+2=0
a=2
b=-5
c=2

$r=\frac{-(-5) \pm \sqrt{(-5)^2-4(2)(2)}}{2(2)}$
$r=\frac{5 \pm \sqrt{25-16}}{4}$
$r=\frac{5 \pm \sqrt{9}}{4}$
$r=\frac{5 \pm 3}{4}$
so
$r=\frac{5+3}{4}=\frac{8}{4}=2$ or $r=\frac{5-3}{4}=\frac{2}{4}=\frac{1}{2}$

use them to solve for the value of a
$\frac{-1}{5}=ar$
$\frac{-1}{5r}=a$
try for r=2 and 1/2
$a=\frac{-1}{10}$ or $a=\frac{-2}{5}$

test each
for a=-1/10 and r=2
a+ar+ar²= $\frac{-1}{10}+\frac{-2}{10}+\frac{-4}{10}=\frac{-7}{10}$
it works

for a=-2/5 and r=1/2
a+ar+ar²= $\frac{-2}{5}+\frac{-1}{5}+\frac{-1}{10}=\frac{-7}{10}$
it works

both have the same terms but one is simplified

the 3 numbers are $\frac{-2}{5}$ , $\frac{-1}{5}$ , and $\frac{-1}{10}$

6 0

4 years ago

Can a triangle be formed with the sides lengths of 8 cm, 5 cm and 13 cm?

Anni [7]

The rule says that the sum of any two sides has to be smaller than the third side so, no it can't

4 0

3 years ago

Solve ( x - 2)( x + 7) =0

lara31 [8.8K]

Answer:

x = 2 or

x = -7

Step-by-step explanation:

(x - 2)(x + 7) = 0

x - 2 = 0

Add 2 to both sides

x - 2 + 2 = 2 + 0

x = 2

x + 7 = 0

Subtract 7 from both sides

x + 7 - 7 = 0-7

x = -7

Therefore

x = 2 or

x = -7

6 0

3 years ago

What is 80% of 25 help me

sladkih [1.3K]

(i have to make this 20 characters long)
80% of 25 is 20

7 0

3 years ago