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3 years ago

How does multiplying powers with the same base from multiplying powers with the same exponent but different bases

Mathematics

2 answers:

Levart [38]3 years ago

7 0

Answer:

Step-by-step explanation:

I'm not positive about what you're asking. So I'm going to explain what I think you're asking.

Multiplying powers with the same base.

Example 2 to the 2nd time the 3rd.

2^2X3= 2^6 Meaning you have 2 times it's self two times and then two more times and then two more times. 2X2 X 2X2 X 2X2

Or two time three is six, so you have two raised to the sixth power...two times itself six times. 2X2X2X2X2X2

3^3 X 9^3

If you have the same exponent with different bases, you multiply each base the correct number of times...3^3 would be 3X3X3 and 9^3 would be 9X9X9

9^3=729 and 3^3=27 and then multiply those two products 729X27=19,638

I hope that helps.

fomenos3 years ago

3 0

Answer:

when you multiply two numbers or variables with the same base,you simply add the exponents. When you multiply expressions with the same exponent but diffrent bases,you multiply the bases and use the same exponent

Step-by-step explanation:

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Burka [1]

Answer:

Step-by-step explanation:

$F \alpha \frac{1}{d^{2} }$

$F = \frac{K}{d^{2} }$

When F = 18; d = 2

$18 = \frac{K}{2^{2} }$

$18 = \frac{K}{4}$

Cross multiply;

18 x 4 = K

72 = K

There the equation connecting F and $d^{2}$ is

$F = \frac{72}{d}$

Now, Find F when d = 6

All you do is to substitute d = 6 in to $F = \frac{72}{d}$

$F = \frac{72}{6}$

Therefore;

F = 12

Please mark me brainiest if correct.

6 0

2 years ago

What is the solution of the following? *<br> -4 = 16<br> Infinite solutions<br> no solution

rjkz [21]

Answer: no solution

Hope this helps and good luck :)

Step-by-step explanation:

8 0

2 years ago

Vanessa deposits $24,000 into each of two savings accounts. Account I earns 2. 4% interest compounded annually. Account II earns

ikadub [295]

The sum of the balances of these accounts at the end of 5 years is given by: Option B: $53,901.59 (approx)

<h3>How to calculate compound interest's amount?</h3>

If the initial amount (also called as principal amount) is P, and the interest rate is R% per unit time, and it is left for T unit of time for that compound interest, then the interest amount earned is given by:

$CI = P(1 +\dfrac{R}{100})^T - P$

The final amount becomes:

$A = CI + P\\A = P(1 +\dfrac{R}{100})^T$

<h3>How to calculate simple interest amount?</h3>

If the initial amount (also called as principal amount) is P, and the interest rate is R% annually, and it is left for T years for that simple interest, then the interest amount earned is given by:

$I = \dfrac{P \times R \times T}{100}$

For the considered case, we're given that:

Initial amount in both accounts deposited = $24,000 = P
Type of interest: Compound interest in first account and simple interest in second account
Unit of time: Annually
Rate of interest = 2.4% annually = R
Total unit of time for which amount is to be calculated: 5 years = T

In first account, the final amount at the end of 5 years is evaluated as:

$A = 24000(1 + \dfrac{2.4}{100})^4 = 24000(1.024)^4 \approx 27021.59\: \rm (in \: dollars)$