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Arada [10]
3 years ago
8

PLS I NEED HELP ITS IMPORTANT I AM GIVING 25 POINTS HELP PLEASE. I NEED IT FAST

Chemistry
2 answers:
kupik [55]3 years ago
8 0

Answer:

B

Explanation: Since you need this quick, its because it needs to respond to the environment. I dont remember the exact term  

Svetlanka [38]3 years ago
4 0

Answer:

A,B, and D

Explanation:

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Explain why the electron configuration of 2-3-1 represents an atom in an excited state?
baherus [9]

Answer:

See explanation

Explanation:

If we look at the electron configuration closely, we will discover that the element must have had a ground state electron configuration of 2,4.

This is because, the innermost shell usually holds two electrons while the outer shells hold eight electrons each. The four electrons must be accommodated in the second shell in the ground state configuration of the compound.

However, when the atom is excited, one electron from this shell may move to the third shell to give the excited state configuration 2-3-1 as shown in the question.

6 0
3 years ago
According to the periodic table of the elements, which set of elements has similar properties?
erma4kov [3.2K]
In chemistry, "chemical properties" of elements usually refers to the electron affinity of an atom (number of valence electrons) This is because atoms with the same number of valence electrons will form similar compounds with other atoms, and undergo the same types of reactions.

Out of this list: He, Ne and Ar are all group 18 elements (Noble gases)
Therefore they have similar chemical properties.
8 0
3 years ago
The type of energy present in the bonds between atoms is
Wittaler [7]
Ionic bonds, metallic bonds and hydrogen bonds, and covalent bonds.
6 0
3 years ago
Calcium carbonate decomposes at high temperatures to give calcium oxide and carbon dioxide as shown below. CaCO3(s) CaO(s) + CO2
romanna [79]

Answer:

\boxed{\text{10.0 g}}

Explanation:

The balanced equation is

CaCO₃(s) ⇌ CaO(s) + CO₂(g); Kp = 1.16

Calculate Kc

T= 800 °C = 1073 K; Δn= 1

K_{\text{p}} = K_{\text{c}}{RT}^{\Delta n}\\\\1.1 = K_{c}{(RT)}^{1}\\\\K_{c} = \dfrac{1.1}{RT} = \dfrac{1.1}{8.314\times 1073}= \dfrac{1.1}{8921} = 1.233 \times 10^{-4}

Equilibrium concentration of CO₂

K_{c} = [\text{CO}_{2}] = 1.233 \times 10^{-4}

Moles of CO₂ formed

n= \text{5.00 L } \times \dfrac{\text{1.233 $\times$ 10$^{-4}$ \text{ mol} }}{\text{1 L}} = 6.155 \times 10^{-4}\text{ mol}

Moles of CaCO₃ used up

Moles of CaCO₃ used up = moles of CO₂ formed = 6.155 × 10⁻⁴ mol

Mass of CaCO₃ used up

m = 6.155 \times 10^{-4}\text{ mol } \times \dfrac{\text{100.09 g}}{\text{1 mol}} = \text{0.0616 g}

Moles of CaO formed

Moles of CaO formed = moles of CO₂ formed = 6.155 × 10⁻⁴ mol

Mass of CaO formed

m = 6.155 \times 10^{-4}\text{ mol } \times \dfrac{\text{56.08 g}}{\text{1 mol}} = \text{0.0345 g}

Mass of solid at equilibrium

m = 10.0 g – 0.0616 g + 0.0345 g = 10.0 g

\text{The mass of solid remaining at equilibrium is } \boxed{\textbf{10.0 g}}

6 0
3 years ago
A water molecule is polar because:
Karo-lina-s [1.5K]

Answer:

the attractions between molecules shift the charges within molecules

8 0
3 years ago
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