All categories

3 years ago

How is stoichiometry used to calculate amount of product from amount of reactant?

Chemistry

1 answer:

Nadusha1986 [10]3 years ago

5 0

Answer:

D. The coefficients give the ratio of mole reactant to moles product.

Explanation:

In stoichiometric calculations, the amount of product formed from reactants can be determined.

Using this approach, the number of moles of reactants and products on both sides of the expression must be balanced.
As a rule of thumb, the coefficients give the ratio of moles of reactants to moles of products.
This is very useful in a number of calculations using the stoichiometric approach.

You might be interested in

4 Na + O2 → 2 Na2O 6.79 moles of O2 will react to form how many moles of Na2O?

Nataly_w [17]

Answer:

13.94moles of Na₂O

Explanation:

The balanced reaction expression is given as:

4Na + O₂ → 2Na₂O

Given parameters:

Number of moles of O₂ = 6.97moles

Unknown:

Number of moles of Na₂O

Solution:

To solve this problem;

1 mole of O₂ will produce 2 moles of Na₂O ;

6.97 moles of O₂ will produce 6.97 x 2 = 13.94moles of Na₂O

6 0

3 years ago

Calculate the number of milliliters of 0.440 M KOH required to precipitate all of the Fe2+ ions in 187 mL of 0.692 M FeSO4 solut

EleoNora [17]

Answer:

588.2 mL

Explanation:

FeSO₄(aq) + 2KOH(aq) → Fe(OH)₂(s) + K₂SO₄(aq)

First we calculate how many Fe⁺² moles reacted, using the given concentration and volume of FeSO₄ solution (the number of FeSO₄ moles is equal to the number of Fe⁺² moles):

moles = molarity * volume

187 mL * 0.692 M = 129.404 mmol Fe⁺²

Then we convert Fe⁺² moles to KOH moles, using the stoichiometric ratios:

129.404 mmol Fe⁺² * $\frac{2mmolKOH}{1mmolFeSO_4}$ = 258.808 mmol KOH

Finally we calculate the required volume of KOH solution, using the given concentration and the calculated moles:

volume = moles / molarity

258.808 mmol KOH / 0.440 M = 588.2 mL

6 0

3 years ago

Define or explain the following terms. a) Equilibrium constant expression - b) Equilibrium constant - c) Absorbance - d) Beer's

tankabanditka [31]

Explanation:

(a) Equilibrium constant expression is ratio of concentrations of products over reactants each raised to their power of stoichiometric coefficients.

For example consider an equilibrium which is:

$aA+bB\rightleftharpoons cC+dD$

The expression is:

$K_c=\frac {[C]^c[D]^d}{[A]^a[B]^b}$

(b) Equilibrium constant of the chemical reaction is value of the reaction quotient of the reaction at the stage of chemical equilibrium which is a state that is approached by the dynamic chemical system at which the composition of the reactant and the product has no measurable tendency towards the change.

(c) Absorbance is the measure of capacity of the substance to absorb the light of a specific wavelength. Absorbance is equal to the logarithm of reciprocal of transmittance.

(d) The Beer's law relates attenuation of the light to properties of material through which light is travelling.

The expression for the law is:

A = ε × l× c

Where,

A is the absorbance

ε is molar absorptivity coefficient

l is the path length

c is the concentration.

3 0

3 years ago

Which functional group is found in methanol?

denis23 [38]

Yes , CH3OH - this is methanol

8 0

3 years ago

Read 2 more answers

Which substance in each of the following pairs would you expect to have the higher boiling point? Explain why.

satela [25.4K]

Explanation:

Boiling point is defined as the temperature when the vapor pressure of liquid becomes equal to the atmospheric pressure surrounding the liquid. And, during this temperature liquid state of substance changes into vapor state.

More stronger is the presence of intermolecular forces within the molecules of a compound more heat is required by it to break the bond. Hence, boiling point will also increase.

(a) As both Ne and Xe are noble gases and has intermolecular dispersion forces. But as the atomic size of Xe is more than the atomic size of Ne and we know that dispersion forces increases with increase in size.

Hence, boiling point of Xe will be more than the boiling point of Ne.

(b) Both $CO_{2}$ and $CS_{2}$ are non-polar in nature with intermolecular dispersion forces. So, more is the molecular weight of a compound more heat will be required by it in order to break the bonds.

As molecular weight of $CS_{2}$ is more than the molecular weight of $CO_{2}$ . Hence, $CS_{2}$ will have high boiling point.

(c) Molecular weight of $CH_{4}$ is 16 g/mol and molecular weight of $Cl_{2}$ is 35 g/mol.

Hence, $Cl_{2}$ will have high boiling point due to the presence of high molecular weight as compared to $CH_{4}$ and more strong dispersion forces.

(d) $F_{2}$ is a covalent compound so, it will also be non-polar in nature. Hence, it has weak intermolecular dispersion forces. On the other hand, LiF is an ionic compound and it has strong intermolecular forces of attraction due to the presence of opposite charges on the combining atoms.

Hence, LiF will have high boiling point as compared to $F_{2}$ .

(e) Both $NH_{3}$ and $PH_{3}$ are polar molecules in which dipole-dipole forces does exist. Since, nitrogen atom is more electronegative than phosphorous atom so, it will have stronger hydrogen bonding and strong intermolecular forces.

Hence, $NH_{3}$ will have high boiling point as compared to $PH_{3}$ .

8 0

3 years ago