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Elden [556K]
4 years ago
8

An aqueous HCL solution has a proton concentration equal to 6.00 mol/L. The HCL concentration in this solution is ————M.

Chemistry
1 answer:
Harman [31]4 years ago
4 0

Answer:

HCl conc.= 6.0mol/L

Explanation:

From the dissociation of HCl= 1 mole H+ and 1mol Cl-, which is equivalent stoichiometrically in concentration to that of 1 mol HCl,

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A saturated solution of AgCl is treated with solid NaCl until the [Cl−] is 0.46 M. What will be the resulting [Ag+] in solution?
Delicious77 [7]

Answer:

Check below

Explanation:

Ksp of AgCl = 1.8*10^-10

Ksp = [Ag+] [Cl-]

[Ag+] [Cl-] = 1.8*10^-10

Because [Ag+] = [Cl-] ,

[Ag+]² = 1.8*10^-10

[Ag+] = √((1.8*10^-10)_

[Ag+] = 1.35*10^-5M

That is [Ag+] in the original saturated solution.

NaCl is added to the saturated AgCl solution:

If Cl- = 0.72M , equation becomes

[Ag+] [ 0.72] = 1.8*10^-10

[Ag+] = (1.8*10^-10)/0.72

[Ag+] = 2.5*10^-10M

% Ag+ remaining in solution =(2.5*10^-10) / { (1.35*10^-5) * 100

% Ag+ remaining = 1.85*10^-3% or 0.00185%

Note that an approximation has been made here: [Cl-] is 0.72M + the unprecipitated Cl- from the AgCl. Because this latter is an infinitely small amount compared to 0.72M , it is quite safe to make this approximation without any effect on the answer.

220

4 0
3 years ago
What type of mixture contains the largest particles
tia_tia [17]
A suspension is the mixture with the largest particles.
6 0
3 years ago
An atom with 17 protons, 18 neutrons, and 18 electrons will have a charge of
mr_godi [17]

Answer:

It's atomic mass is 35

Explanation:

8 0
4 years ago
Read 2 more answers
I need help fast
jarptica [38.1K]
It would be 1/2beacise I said so
6 0
4 years ago
A sample of the male sex hormone testosterone, C19H28O2, contains 3.88×10^21 atoms of hydrogen.
Ann [662]

Answer:- (a) 2.63*10^2^1Catoms (b)  1.39*10^2^0molecules (c) 2.30*10^-^4mole  (d) 0.663 grams

Solution:- (a) Number of atoms of hydrogen are given and it asks to calculate the number of atoms of carbon. The given molecule has 19 carbons and 28 hydrogens. So, the ratio of atoms of C to H is 19:28.

Let's make multiply the given number of atoms of H by the ratio to get the atoms of C.

3.88*10^2^1Hatoms(\frac{19Catoms}{28Hatoms})

= 2.63*10^2^1Catoms

(b) One molecule of testosterone contains 28 atoms of H. So, the ratio is 1:28. Let's multiply the given number of atoms of H by this ratio to get the number of molecules of testosterone.

3.88*10^2^1Hatoms(\frac{1molecule}{28Hatoms})

= 1.39*10^2^0molecules

(c) To calculate the moles, we divide the molecules by Avogadro number.

 = 1.39*10^2^0molecules(\frac{1mole}{6.022*10^2^3molecules})

= 2.30*10^-^4mole

(d) To get the mass of the sample we multiply the moles by the molar mass. Molar mass of testosterone = 19(12.01)+28(1.01)+2(16)

= 228.19+28.28+32

= 288.47 gram per mol

let's multiply the moles of the above part by molar mass to get the mass.

2.30*10^-^4mole(\frac{288.47g}{1mol})

= 0.663 grams

4 0
3 years ago
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