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MrRa [10]
3 years ago
12

Use the information to solve the triangle. Round your answers to two decimal places. Hint: draw a sketch first to determine if y

ou should use Law of Sines or Cosines.
B=100°, a=15, b=23
Mathematics
1 answer:
tatyana61 [14]3 years ago
6 0

Answer:

A = 40.0 (3 sig. fig)

C = 40

c = 15

Step-by-step explanation:

Using sin law,

sinA/15 = sin100/23

A = 40.0 (3 sig. fig)

Using angle sum of triange,

C = 180 - 40.0 - 100 = 40

Since angleA = angleC, by side equal opp angles, c = 15

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Answer:

(3−5)(+1)

Step-by-step explanation:

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2 years ago
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ra1l [238]

Answer: 350/12

I think 29 2/12 can be also true because they didn't simplify the 2/12 to 1/6.

Step-by-step explanation:

You'll have to use the basic formula for volume is length × width × height. The sample box has the area of 23 1/3 which is found by length x width. They give you the height 1 1/4. I am assuming you will need to multiply 23 1/3 by 1 1/4. You'll get 350/12.

If it's simplify further it will be 175/6 or 29 1/6 as a mixed fraction.

7 0
3 years ago
PLS HELP NEED ANSWERS QUICK WILL GIVE BRAINLIEST
yawa3891 [41]

Answer:

a- 10x^2 - 4x + 12

b- no, the first equation is −1/4⋅(5x^2+6x−24) and the second is -1/4⋅(10x^2+7x-24)

Step-by-step explanation:

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7 0
2 years ago
A rectangular box has the dimensions shown in the diagram. The volume of the box is given by the function V(x) = x^3 – 4x, where
madreJ [45]

Answer:

length, width, and height are (b+2), (b-2), (b+3)

Step-by-step explanation:

Doing what the problem statement tells you to do, you get ...

 (b^3 +3b^2) -(4b +12)

 = b^2(b +3) -4(b +3) . . . . . factor each pair of terms

 = (b^2 -4)(b +3) . . . . . . . . . write as a product

 = (b -2)(b +2)(b +3) . . . . . . use the factoring of the difference of squares

The three factors are (b-2), (b+2), and (b+3). We have no clue as to how to associate those with length, width, and height. We just know these are the dimensions of the box.

Step-by-step explanation:

4 0
3 years ago
Given the formula:<br><img src="https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B1%20%2B%20a%7D%7B1%20-%20a%7D%20" id="TexFormula1
shtirl [24]

12 = \frac{1+a}{1-a} => 12(1-a)= 1+ a \\=> 12 -12a = 1 + a => 12a+1 = 12-1 \\=> 13a = 11 => a= \frac{11}{13}

ok done. Thank to me :>

8 0
2 years ago
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