A) Demand function
price (x) demand (D(x))
4 540
3.50 810
D - 540 810 - 540
----------- = -----------------
x - 4 3.50 - 4
D - 540
----------- = - 540
x - 4
D - 540 = - 540(x - 4)
D = -540x + 2160 + 540
D = 2700 - 540x
D(x) = 2700 - 540x
Revenue function, R(x)
R(x) = price * demand = x * D(x)
R(x) = x* (2700 - 540x) = 2700x - 540x^2
b) Profit, P(x)
profit = revenue - cost
P(x) = R(x) - 30
P(x) = [2700x - 540x^2] - 30
P(x) = 2700x - 540x^2 - 30
Largest possible profit => vertex of the parabola
vertex of 2700x - 540x^2 - 30
When you calculate the vertex you find x = 5 /2
=> P(x) = 3345
Answer: you should charge a log-on fee of $2.5 to have the largest profit, which is $3345.
Answer:
6
Step-by-step explanation: think of it this way. When you adding a positive to a negative, you simply taking the negative away from the positive. So in this case, you are subtracting 2 from 8 to get six. Or, its the difference between the positve and the negative!! Hope this helps!
Answer:
X= 15
Step-by-step explanation:
the above equation will be used to determine the value of x.
the above equation will be used to determine the value of x.
6x-12= 2x+20+18
6x-2x = 20+12+18
4x= 60.
X= 60/4
X= 15
x = 15
No, you would only need to multiply 16 by 5 once